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solniwko [45]
3 years ago
9

A training field is formed by joining a rectangle and two semicircles. The semicircles are attached on opposite sides of the rec

tangle. The diameter of each semicircle is also one of the shorter sides of the rectangle. The rectangle is long and wide. What is the length of a training track running around the field? (Use the value for , and do not round your answer. Be sure to include the correct unit in your answer.)
Mathematics
1 answer:
Anarel [89]3 years ago
5 0

Step-by-step explanation:

There is figures in you question. Please check your question.

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Answer:

105 degrees

Step-by-step explanation:

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I think it's 76 degrees
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Customers arrive at a grocery store at an average of 2.1 per minute. Assume that the number of arrivals in a minute follows the
Black_prince [1.1K]

Answer:

a)  P(2)=0.270

b) P(X>3)=0.605

c)  P=0.410

Step-by-step explanation:

We know that customers arrive at a grocery store at an average of 2.1 per minute. We use the  Poisson distribution:

\boxed{P(k)=\frac{\lambda^k \cdot e^{-\lambda}}{k!}}

a)  In this case: \lambda=2.1

P(2)=\frac{2.1^2 \cdot e^{-2.1}}{2}\\\\P(2)=0.270

Therefore, the probability is P(2)=0.270.

b)  In this case: \lambda=2\cdot 2.1=4.2

P(X>3)=1-P(X\leq 3)\\\\P(X>3)=1-\sum_{x=0}^3 \frac{4.2^x \cdot e^{-4.2}}{x!}\\\\P(X>3)=1-0.395\\\\P(X>3)=0.605

Therefore, the probability is P(X>3)=0.605.

c)  We know that two customers came in in the first minute. That is why we calculate the probability of at least 5 customers entering the other 2 minutes.

In this case: \lambda=2\cdot 2.1=4.2

P(X\geq 5)=1-P(X

Therefore, the probability is P=0.410.

4 0
3 years ago
Combine the like terms to create an equivalent expression.<br><br> 10k+1+8k+2
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A drawer has a volume of 1575 cubic inches. the drawer is 5 inches deep and 21 inches long. What is the width of the drawer?
katrin [286]
Volume is l × w × h
l = 21 in
h = 5 in
w = ?
volume = 1575 in

21 × 5 × w = 1575
105 × w = 1575
w = 1575 ÷ 105
w = 15 inches
3 0
3 years ago
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