Remember the rules of Sohcahtoa (Sine, cosine, tangent). For this problem we take the cosine of 38 because the labeled sides are the adjacent leg and the hypotenuse.
Cos(38)=79/x
Cosine of 38 is about 0.7880
0.7880=79/x
Next we multiply both sides by the denominator
(x) 0.7880=79 (x)
Then divide.
<u>0.7880x</u>= <u>79</u>
0.7880 0.7880
X=100.25
Hope this helped :)
In
order to solve for a nth term in an arithmetic sequence, we use the formula
written as:<span>
an = a1 + (n-1)d
where an is the nth term, a1 is the first value
in the sequence, n is the term position and d is the common difference.
First, we need to calculate for d from the given
values above.
<span>a3 = 20.5 and a8 = 13
</span>
an = a1 + (n-1)d
20.5 = a1 + (3-1)d
</span>an = a1 + (n-1)d
13 = a1 + (8-1)d
<span>
a1 = 23.5
d = -1.5
The 11th term is calculated as follows:
a11 = a1 + (n-1)d
a11= 23.5 + (11-1)(-1.5)
a11 =
8.5</span>
Answer:
o solve an quadratic equation using factoring : 1 . Transform the equation using standard form in which one side is zero. ... Set each factor to zero (Remember: a product of factors is zero if and only if one or more of the factors is zero).
Step-by-step explanation:
Answer: So, your relative takes N tablets each 6 hours. a day has 24 hours, and 24/6 = 4, so he takes N tablets 4 times per day, so he takes 4*N tablets.
each tablet has 200mg, and 2.3 g (or 2300 mg) is toxic.
this means that 4*N*200mg must be less than 2300, if we are seeking for the maximum N possible, then:
4*N*200mg = 2300mg
4*N = 2300/200 = 11.5
N = 11.5/4 = 2.87
if you round up this number, you will end up taking more than 2.3g of tylenol per day, this implies that N must be equal to 2.
So your relative needs to take maximum 2 tablets per day.
