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3 years ago

If there are 12 boys and 20 students, write as a ratio for boys to students in 3 ways.

Mathematics

1 answer:

ruslelena [56]3 years ago

3 0

12:20

6:10

3:5

Hope that helps :)

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Which theorem would you use to prove ABE ~ DCE?

Pachacha [2.7K]

Answer: Choice C) AA similarity

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We are given that angle ABE = angle ECD since they are both right angles (square marker)

Angle AEB = angle CED as they are vertical angles

we have two pairs of congruent angles, leading us to be able to use the AA (angle angle) similarity theorem

3 0

3 years ago

Lotteries are an important income source for various governments around the world. However, the availability of lotteries and ot

SashulF [63]

Answer: 0.0473

Step-by-step explanation:

Given : The proportion of gambling addicts : p=0.30

Let x be the binomial variable that represents the number of persons are gambling addicts.

with parameter p=0.30 , n= 10

Using Binomial formula ,

$P(x)=^nC_xp^x(1-p)^{n-x}$

The required probability = $P(x>5)=P(6)+P(7)+P(8)+P(9)+P(10)\\\\=^{10}C_6(0.3)^6(0.7)^{4}+^{10}C_7(0.3)^7(0.7)^{3}+^{10}C_8(0.3)^8(0.7)^{2}+^{10}C_9(0.3)^9(0.7)^{1}+^{10}C_{10}(0.3)^{10}(0.7)^{0}\\\\=\dfrac{10!}{4!6!}(0.3)^6(0.7)^{4}+\dfrac{10!}{3!7!}(0.3)^7(0.7)^{3}+\dfrac{10!}{2!8!}(0.3)^8(0.7)^{2}+\dfrac{10!}{9!1!}(0.3)^9(0.7)^{1}+(1)(0.3)^{10}\\\\=0.0473489874\approx0.0473$

Hence, the required probability = 0.0473

5 0

3 years ago

What is the greatest perfect square of 1290

Alex73 [517]

<span>It has no perfect square factors, unless you count 1 = 1^2. That's sort of a degenerate case we don't usually count, since every integer has that factor. We would usually say that 1290 is a square-free integer. Hope this helps!!</span>

6 0

3 years ago

Read 2 more answers

A projectile is launched from ground level with an initial velocity of v0 feet per second. Neglecting air resistance, its height

elena-s [515]

The formula is $s=-16t^2+V_ot$

We have:
$s=64$
$V_o=80ft/s$

Substituting these values into the formula, we have

$64=-16t^2+80t$

$16t^2-80t+64=0$ ⇒ divide each term by 16

$t^2-5t+4=0$ ⇒ find the pair of numbers that multiply to give 4 and sum gives -5 which is -1 and -4

$(t-1)(t-4)=0$ ⇒ We have two values of t

$t-1=0$ ⇒ $t=1$
$t-4=0$ ⇒ $t=4$

The time when the projectile reached 64 feet is at t=1 and t=4

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3 years ago

Describe how you would find the rate of change from a graph?

Lina20 [59]

I think it’s rise over run but it might not be

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3 years ago