If there are 12 boys and 20 students, write as a ratio for boys to students in 3 ways.

Albert sells furniture. His base salary is $300 per week, plus 5.5% commission. If his total sales for last week were $2950, wha

Andreas93 [3]

Answer:

16225

Step-by-step explanation:

You need to multiply

5 0

3 years ago

Which of the following is NOT a requirement of testing a claim about a population proportion using a formal method of hypothesis

Pie

Answer:

A. The lowercase symbol, p, represents the probability of getting a test statistic at least as extreme as the one representing sample data and is needed to test the claim.

Step-by-step explanation:

The conditions required for testing of a claim about a population proportion using a formal method of hypothesis testing are:

1) The sample observations are a simple random sample.

2) The conditions for a binomial distribution are satisfied

3) The conditions np5 and nq5 are both satisfied. i.e n: p≥ 5and q≥ 5

These conditions are given in th options b,c and d.

Option A is not a condition for testing of a claim about a population proportion using a formal method of hypothesis testing.

8 0

2 years ago

A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the

Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average age = 25 years

$\sigma$ = population standard deviation = 1.8 years

n = sample of students = 36

$\mu$ = population average age

So, 98% confidence interval for the average age, $\mu$ is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.3263) = 0.98

P( $-2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < ${\bar X - \mu}$ < $2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

P( $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < $\mu$ < $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ , $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ]

= [ $25 - 2.3263 \times {\frac{1.8}{\sqrt{36} }$ , $25 + 2.3263 \times {\frac{1.8}{\sqrt{36} }$ ]

= [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0

2 years ago

Help help help help pls

Yanka [14]

Answer:

x - 3 > 10

Step-by-step explanation:

3 0

3 years ago

While completing a multiplication problem I need to know how to do it by associative

Vera_Pavlovna [14]

Associative property Says that you can add or multiply regardless of how the numbers are group

3 0

3 years ago