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pychu [463]
3 years ago
15

Which expression is equivalent to 16^3?

Mathematics
2 answers:
Rzqust [24]3 years ago
8 0

I think the answer is 2^12

because ...

16^3 is equal to 4,096

and 2^12 is also equal to 4,096

ANEK [815]3 years ago
4 0

Answer:

The answer is 2^12

Step-by-step explanation:

Its on Edge

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Answer:

Steps For Solving Real World Problems

2. Highlight the important information in the problem that will help write two equations.

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6. Check your answers by substituting your ordered pair into the original equations.

4 0
3 years ago
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HELP ASAP PLEASE.
Schach [20]

Answer:

5(6)81 because the are

Step-by-step explanation:

6•82

8 0
3 years ago
WRITE A EQUATION ''THE QUOTIENT OF A NUMBER AND 20.7 is 9
zhannawk [14.2K]

Answer:

186.3

To find the answer you have to do inverse operations

9×20.7=186.3

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3 0
3 years ago
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Sara is mixing together a fruit punch for a party. She's made 4 gallons of punch with a mixture of 50% juice. Her mother tells h
Nata [24]
\bf \begin{array}{lccclll}
&amount(gallons)&juice&\textit{juice amount}\\
&--------&-----&-----\\
\textit{50\% punch}&4&0.50&(4)(0.50)\\
\textit{pure juice}&x&1.00&(x)(1.00)\\
-----&-----&-----&-----\\
mixture&4+x&0.60&(4+x)(0.60)
\end{array}

notice, that, pure juice is 100% juice, dohhh, thus 100/100 = 1.00
50% is 50/100 or 0.50 in decimal format

so..... whatever those two quantities amount to, that is, the 50% and pure juice, or (4)(0.50) + (x)(1.00)
they will equal the mixture desired 60% juice, or 0.60, namely (4+x)(0.60)

thus    (4)(0.50) + (x)(1.00) = (4+x)(0.60)

solve for "x"
4 0
3 years ago
Find a positive number for which the sum of it and its reciprocal is the smallest​ (least) possible. Let x be the number and let
Allisa [31]

Answer:

S(x) = x + \frac{1}{x} --- Objective function

Interval = \{x:x=1\}

Step-by-step explanation:

Given

Represent the number with x

The required sum can be represented as:

x + \frac{1}{x}

Hence, the objective function is:

S(x) = x + \frac{1}{x}

To get the the interval, we start by differentiating w.r.t x

<em>Using first principle, this gives:</em>

S'(x) = 1 - \frac{1}{x^2}

Equate S'(x) to 0 in order to solve for x

0 = 1 - \frac{1}{x^2}

Subtract 1 from both sides

0 -1 = 1 -1 - \frac{1}{x^2}

-1 = - \frac{1}{x^2}

Multiply both sides by -1

1 = \frac{1}{x^2}

Cross Multiply

x^2 * 1 = 1

x^2  = 1

Take positive square root of both sides because x is positive

\sqrt{x^2} = \sqrt{1

x = 1

Representing x using interval notation, we have

Interval = \{x:x=1\}

To get the smallest sum, we substitute 1 for x in S(x) = x + \frac{1}{x}

S(1) = 1 + \frac{1}{1}

S(1) = 1 + 1

S(1) = 2

<em>Hence, the smallest sum is 2</em>

3 0
3 years ago
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