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ale4655 [162]
3 years ago
14

Which function is most likely graphed on the coordinate plane below? What is the equation of the line perpendicular to 2x – 3y =

13 that passes through the point (–6, 5)?
Y=2/3 x +9
Y=-3/2x-4
Y=-3/2 x -13
Y=2/3x-1
Mathematics
1 answer:
masha68 [24]3 years ago
4 0

Answer:

y=\frac{-3}{2}x-4

Step-by-step explanation:

the equation of the line perpendicular to 2x – 3y = 13

It passes through the point (–6, 5)

2x -3y = 13

Subtract 2x from both sides

-3y =-2x+13

Divide both sides by -3

y=\frac{2}{3}x-\frac{13}{3}

Slope = 2/3

Slope of perpendicular lines are negative reciprocal of one another

slope of perpendicular line is \frac{-3}{2}

Point (-6,5)

y-y1=m(x-x1)

y-5=\frac{-3}{2}(x+6)

y-5=\frac{-3}{2}x-9

Add 5 on both sides

y=\frac{-3}{2}x-4

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