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liberstina [14]
3 years ago
6

Rachel collected 56 rocks at the beach. She is placing them into bags to give to her friends. She says that if she puts 4 rocks

in each bags, she will have 16 rocks left after she makes 10 bags. Is she correct
Mathematics
2 answers:
svlad2 [7]3 years ago
7 0
Yes. 4 x 10 is 40. 56 - 40 is 16.
borishaifa [10]3 years ago
4 0
Yes, she is correct

4 x 10 = 40

56 - 40 = 16

You might be interested in
James used a substitution to solve this system of equations. Which equation could be a result of his first step? 2x+3y=12 y=x+1.
Blizzard [7]

Answer:

x = 1.5

y = 3

Step-by-step explanation:

to solve this system of equation using the substitution methods we say let

2x+3y=12................................... equation 1

y=x+1.5..................................... equation 2

substitute equation 2  into equation 1

2x+3y=12................................... equation 1

2x + 3( x + 1.5) = 12

2x + 3x + 4.5 = 12

5x + 4.5 = 12

collect the like terms

5x = 12 - 4.5

5x = 7.5

divide both sides by the coefficient of x which is 5

5x/5 = 7.5/5

x = 1.5

put x = 1.5 into equation 2

y=x+1.5..................................... equation 2

y = 1.5 + 1.5

y = 3

therefore the value of x = 1.5 and y = 3 respectively.

5 0
3 years ago
Explain why the graph below does not represent a direct variation. a. the line does not intercept the x-axis c. the line does no
Rama09 [41]

The graph is not a direct variation because the line does not go through the origin; option C.

<h3>What is a direct variation?</h3>

A direct variation is a relationship between two or more quantities in which as one quantity increases, the other quantity also increases. Similarly, if the other quantity decreases, the other decreases as well.

For the graph of a direct variation, the line must pass through the origin.

Therefore, the graph does not represent a direct variation because the line does not go through the origin.

In conclusion, direct variation involves a corresponding increase or decrease in two related quantities.

Learn more about direct variation at: brainly.com/question/2633726

#SPJ1

3 0
2 years ago
2 tan 30°<br>II<br>1 + tan- 300​
shusha [124]

Question:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Answer:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

Step-by-step explanation:

Given

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Required

Simplify

In trigonometry:

tan(30^{\circ}) = \frac{1}{\sqrt{3}}

So, the expression becomes:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}

Simplify the denominator

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}

Express the fraction as:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= \frac{2}{\sqrt 3} / \frac{4}{3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2}{\sqrt 3} * \frac{3}{4}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{1}{\sqrt 3} * \frac{3}{2}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3}

Rationalize

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3\sqrt{3}}{2* 3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\sqrt{3}}{2}

In trigonometry:

sin(60^{\circ}) =  \frac{\sqrt{3}}{2}

Hence:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

3 0
3 years ago
Select the correct answer. Chloe enjoys her math classes, and she would like to find a career that will allow her to continue to
Arte-miy333 [17]

It would have to be an Accountant.

6 0
2 years ago
Read 2 more answers
Pls do it fast ill mark you brainliest
anygoal [31]

Answer:

\sf  y=7\frac{2}{3} and \sf x = \frac{2}{3}

Explanation:

\sf (1)  \  \  (2x+y = 9)

\sf (1) \ \  (2x+5y = 37)

<u>solve for y</u>:

\sf 2x + y = 9

\sf 2x + 5y = 37

-----------------

\sf 0x + 6y = 46

\sf 6y = 46

\sf  y=\frac{23}{3}

\sf  y=7\frac{2}{3}

<u>solve for x</u>:

\sf 2x + y = 9

\sf 2x = 9 - y

\sf 2x = 9 - \frac{23}{3}

\sf 2x = \frac{4}{3}

\sf x = \frac{2}{3}

8 0
2 years ago
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