Question

Find the area of the trapezoid!!!! PLEASE HELP!!!!

Answer 1

ANSWER

$32 \sqrt{3} {ft}^{2}$

EXPLANATION

The area of a tra-pezoid is half times sum of the bases times the vertical height.

From the diagram ( see attachment) we use the Pythagoras Theorem to obtain,

${x}^{2} + {(4 \sqrt{3}) }^{2} = {8}^{2}$

${x}^{2} + 48 = 64$

${x}^{2} = 64 - 48$

${x}^{2}=16$

$x = \sqrt{16} = 4ft$

This implies that , y=10-4=6ft

The area of tra-pezoid

$= \frac{1}{2} (10 + 6) \times 4 \sqrt{3}$

$= \frac{1}{2} (16) \times 4 \sqrt{3}$

$= 8\times 4 \sqrt{3}$

$= 32 \sqrt{3} {ft}^{2}$