equation has infinitely many solutions has the same number on both sides of the equal sign
-3x -21 + x + 5 = -20x -16
-2x -16 = -20x -16
so either you have -18x on the left or +18x in the right
<span>The correct answer is option B. i.e. Both equation 1 and 2 have the same number of solutions. The equation 1 is |5x+6| = 41 By removing the modulus sign we get, 5x + 6 = 41 and 5x +6 = -41. Solving, 5x = 6 = 41 we get, 5x = 35 or x = 7. And, on solving 5x +6 = -41 we get, 5x = -47 or x = 9.4 Now. the second equation is |2x+13| = 28 By removing the modulus sign we get, 2x+ 13 = 28 and 2x +13 = -28. Solving, 2x = 28 -13 = 15 or x = 7.5 . And, on solving 2x +13 = -28 we get, 2x = -41 or x = -20.5.TH </span>
Answer:
The second one and the fourth one :)
Since this is out of 4, you can think of 4 as being 1. Now each part of 4 needs to have an equal value so you need to split 1 into 4 equal values. So half of 1 is 0.5 and half of 0.5 is 0.25. So, each part of 4 has a value of 0.25.
1/4 = 0.25
2/4 = 0.50
3/4 = 0.75
