I believe since ABD is 60, DBC is also 60 and then ABC is 120
To find the volume of a box that would hold these nine cylinders, you would start with the formula for volume of a cylinder. V=pi x r^2 x h. Substitute in the known volume and the known Height. 9.425=pi x r^2 x 3. Divide both sides by three to get approximately 3.143 = pi x r^2. Divided by pi on both sides. This leaves you with one = r^2. So the radius is equal to one. If the radius equals one, the diameter is two. Assuming the cylinders are arranged in a 3 x 3 array, the length and width of the rectangle or box would be 6cm x 6cm. To find the volume of the box necessary, multiply the length of six by the width of six by the height of three. The volume would be 108 square cm.
Answer:
-3
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
25-7=18 18/3= 6.
6x3= 18 18+7= 25
THE ANSWER IS 6
