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2 years ago

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A chain store plans to reduce its workforce by 4%. If there are currently 18,600 employees and 126 of them retire voluntarily, h

ow many additional employees must be laid off?
PLEASE SHOW THE WORK !!!!

1 answer:

Alecsey [184]2 years ago

7 0

The number of additional employees who should be laid off to meet target of reducing the workforce by 4% will be as follows:
Total number of workers to be laid off will be given by:
(%ge of employees to be laid off)/100×(Total number of employees)
=4/100×18,600
=744 employees
Given that 126 of the quit voluntarily the remaining number that shpuld be laid off will be:
(total number of employees to be laid off)-(number of employees who quit)
=744-126
=618
Therefore we conclude the 618 more employees should be laid off.

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b) 23.61% probability that fewer than 3 tanks will be found to be leaking

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In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

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The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

To solve question c), i am going to approximate the binomial distribution to the normal.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

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This means that $p = 0.25$

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b.What is the probability that fewer than 3 tanks will be found to be leaking?

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$Z = \frac{600 - 500}{19.36}$

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