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andrezito [222]
4 years ago
8

How do i do 5 6 and 9 show work..oh and also 10 13 14 12 15 lol thx

Mathematics
1 answer:
kenny6666 [7]4 years ago
8 0
Number 5 is x = 18 and number 6 is x = -2
You might be interested in
Please help I have tried multiple times but keep getting it wrong.
VladimirAG [237]

Answer:

inequality form: x

x≤ 4 or x≥8

Interval Notation:

(-∞, 4] U[8,∞)

Explanation

Solve the following inequality, then graph the solution set. | x | − 6 ≥ − 4. Answer in interval notation.

3 0
3 years ago
What is the image of (-2,-8) after a reflection over the y-axis?
Papessa [141]

Answer:

(2,8)

Step-by-step explanation:

When you reflect over the y-axis, you change the x to the opposite sign

y reflection → (-x,y)

8 0
4 years ago
Read 2 more answers
You wish to determine the GPA of students at your school. Describe what process you would go through to collect a sample if you
Black_prince [1.1K]

Answer:

simple random sampling

Step-by-step explanation:

6 0
3 years ago
Determine the number and types of solutions for<br><br> 6m^2-3m-4=0
Anna11 [10]

Answer:

2 real solutions

Step-by-step explanation:

Remember this messy thing?

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

The <em>quadratic formula</em>, as it's called, gives us the roots to any quadratic equation in standard form (ax² + bx + c = 0). The information on the <em>type</em> of roots is contained entirely in that bit under the square root symbol (b² - 4ac), called the <em>discriminant</em>. If it's non-negative, we'll have <em>real</em> roots, if it's negative, we'll have <em>complex roots</em>.

For our equation, we have a discrimant of (-3)² - 4(6)(-4) = 9 + 96 = 105, which is non-negative, so we'll have real solutions, and since quadratics are degree 2, we'll have exactly 2 real solutions.

4 0
3 years ago
Suppose a company produces report indicates that the surveyed distance between two points is 1200 feet with a margin of error of
Otrada [13]
<h2>Hello!</h2>

The answers are:

MaximumDistance=1200.1ft\\MinimumDistance=1199.9ft

<h2>Why?</h2>

Since we are given the margin of error and it's equal to ±0.1 feet, and we know the surveyed distance, we can calculate the maximum and minimum distance. We must remember that margin of errors usually involves and maximum and minimum margin of a measure, and it means that the real measure will not be greater or less than the values located at the margins.

We know that the surveyed distance is 1200 feet with a margin of error of ±0.1 feet, so, we can calculate the maximum and minimum distances that the reader could assume in the following way:

MaximumDistance=ActualDistance+0.1feet\\\\MaximumDistance=1200feet+0.1feet=1200.1feet

MinimumDistance=ActualDistance-0.1feet\\\\MaximumDistance=1200feet-0.1feet=1199.9feet

Have a nice day!

4 0
3 years ago
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