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Dafna11 [192]
3 years ago
7

H(y)=-3y^2+5 p(y)=y^3-7y Find (h-p)(y)

Mathematics
1 answer:
gladu [14]3 years ago
5 0

(h-p))(y) = -y^3-3y^2+7y+5

Step-by-step explanation:

Given

h(y) = -3y^2+5\\p(y) = y^3-7y

We have to find the difference of two functions given

So,

(h-p)(y) = h(y) - p(y)\\= (-3y^2+5)-(y^3-7y)\\=-3y^2+5-y^3+7y\\=-y^3-3y^2+7y+5

Hence,

(h-p))(y) = -y^3-3y^2+7y+5

Keywords: Functions, variables

Learn more about functions at:

  • brainly.com/question/10703930
  • brainly.com/question/10772025

#LearnwithBrainly

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