Question

H(y)=-3y^2+5 p(y)=y^3-7y Find (h-p)(y)

Answer 1

$(h-p))(y) = -y^3-3y^2+7y+5$

Step-by-step explanation:

Given

$h(y) = -3y^2+5\\p(y) = y^3-7y$

We have to find the difference of two functions given

So,

$(h-p)(y) = h(y) - p(y)\\= (-3y^2+5)-(y^3-7y)\\=-3y^2+5-y^3+7y\\=-y^3-3y^2+7y+5$

Hence,

$(h-p))(y) = -y^3-3y^2+7y+5$

Keywords: Functions, variables

Learn more about functions at:

• brainly.com/question/10703930
• brainly.com/question/10772025

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