All categories

3 years ago

Are two points collinear

Mathematics

1 answer:

LuckyWell [14K]3 years ago

4 0

Answer:

Step-by-step explanation:

Collinear is if points are on the same line.

2 points are not collinear, as they form a line.

If 3 points were on the same line, then it would be considered collinear.

You might be interested in

WILL GIVE BRAINLIEST! HELP ASAP!

makkiz [27]

Answer:

any nuber less then 3.5 and 5th awnser

Step-by-step explanation:

x is less then 3.5 so any number less then 3.5

5th one is true too because you can go into negitves and tehre is are infanite negitives

7 0

2 years ago

100pts HELP asap divide fractions

statuscvo [17]

6 1/13 for sure
5 14/13 -> 79/13
79/13 to mixed number is 6 1/13

4 0

2 years ago

Read 2 more answers

B2 - 7b + 12 = 0

olga_2 [115]

B2-7b+12=0
(b-3)(b-4)=0
b= 3 or 4

6 0

2 years ago

Read 2 more answers

Find x Thanks for the help in advance!

Marina86 [1]

I'm not sure if this is the easiest way of doing this, but it surely work.

Let the base of the triangle be AB, and let CH be the height. Just for reference, we have

$AH=2,\quad HB=6,\quad AC=x$

Moreover, let CH=y and BC=z

Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system

$\begin{cases}4+y^2=x^2\\36+y^2=z^2\\x^2+z^2=64\end{cases}$

If we solve the first two equations for y squared, we have

$y^2=x^2-4\\y^2=z^2-36$

And we can deduce

$z^2 = x^2+32$

So that the third equation becomes

$x^2+x^2+32=64 \iff 2x^2 = 32 \iff x^2=16 \iff x=4$

(we can't accept the negative root because negative lengths make no sense)

7 0

2 years ago

Evaluate 5a3 + 3b4 when a 4 and b= - 5

valkas [14]

5a^3 + 3b^4

insert the numbers into the equation.

5(4)^3 + 3(-5)^4

evaluate

5(64) + 3(625)

evaluate

320 + 1875

the solution is:

2195

5 0

2 years ago