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4 years ago

Which scenario has been theorizedłas the possible fate of the universe?

Chemistry

1 answer:

Tresset [83]4 years ago

7 0

Answer:

El destino final del universo es una de las cuestiones fundamentales en cosmología física. Muchos destinos posibles son predichos por teorías científicas rivales, incluyendo futuros de duración tanto finita como infinita. Una vez que la noción de que el universo empezó con una rápida inflación apodada el Big Bang, se hizo popular entre la mayoría de los científicos

Explanation:

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Which of the following uses a nonrenewable energy resource to generate energy? A. nuclear power plant B. wind farm C. fireplace

asambeis [7]

The answer is bimass power plant.

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3 years ago

Which wave can travel in both empty space and matter?

vovangra [49]

I believe Choice B is the answer.

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3 years ago

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To identify a diatomic gas (X2), a researcher carried out the following experiment: She weighed an empty 4.6-L bulb, then filled

snow_tiger [21]

Answer:

The chemical formula of the gas is $N_2$ .

Explanation:

The difference between the container with gas and empty container is equal to the mass of the gas.

Let the gas be $X_2$

Mass of the gas = m

Molar mass of diatomic gas = M

Pressure of the gas = P = 1.80 atm

Volume of the gas = V = 4.6 L

Temperature of the gas= T = 27.0 C = 27.0 + 273 K = 300 K

Moles of diatomic gas = n = $\frac{m}{M}$

Using ideal gas equation:

$PV=nRT$

$PV=\frac{m}{M}RT$

$M=\frac{mRT}{PV}=\frac{9.5 grams \times 0.0821 atm L/mol K\times 300 K}{1.80 atm\times 4.6 L}=28.26 g/mol\approx 28 g/mol$

Atomic mass of the element X = $\frac{28 g/mol}{2}=14 g/mol$

The element is nitrogen and the diatomic gas is $N_2$ .

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3 years ago

Match each statement to the type of behavior it describes.

wariber [46]

Answer:

RESPONSIBLE:

1. Joanna aims to develop a scientific product that will improve people's lives.

2. Alisha uses credible research to publish a report about the negative effects of getting insufficient sleep.

IRRESPONSIBLE:

1. Henry was selective in his use of data; he used only the data that supported his hypothesis.

2. Kevin combined data from two unrelated experiments in an effort to impress his instructor.

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4 years ago

Read 2 more answers

When 1.2383 g of an organic iron compound containing Fe, C, H, and O was burned in O2, 2.3162 g of CO2 and 0.66285 g of H2O were

uysha [10]

Answer:

$\boxed{\text{C$_{15}$H$_{21}$FeO$_{6}$}}$

Explanation:

Let's call the unknown compound X.

1. Calculate the mass of each element in 1.23383 g of X.

(a) Mass of C

$\text{Mass of C} = \text{2.3162 g } \text{CO}_{2}\times \dfrac{\text{12.01 g C}}{\text{44.01 g }\text{CO}_{2}}= \text{0.632 07 g C}$

(b) Mass of H

$\text{Mass of H} = \text{0.66285 g }\text{H$_{2}$O}\times \dfrac{\text{2.016 g H}}{\text{18.02 g } \text{{H$_{2}$O}}} = \text{0.074 157 g H}$

(c)Mass of Fe

(i)In 0.4131g of X

$\text{Mass of Fe} = \text{0.093 33 g Fe$_{2}$O$_{3}$}\times \dfrac{\text{111.69 g Fe}}{\text{159.69 g g Fe$_{2}$O$_{3}$}} = \text{0.065 277 g Fe}$

(ii) In 1.2383 g of X

$\text{Mass of Fe} = \text{0.065277 g Fe}\times \dfrac{1.2383}{0.4131} = \text{0.195 67 g Fe}$

(d)Mass of O

Mass of O = 1.2383 - 0.632 07 - 0.074 157 - 0.195 67 = 0.336 40 g

2. Calculate the moles of each element

$\text{Moles of C = 0.63207 g C}\times\dfrac{\text{1 mol C}}{\text{12.01 g C }} = \text{0.052 629 mol C}\\\\\text{Moles of H = 0.074157 g H} \times \dfrac{\text{1 mol H}}{\text{1.008 g H}} = \text{0.073 568 mol H}\\\\\text{Moles of Fe = 0.195 67 g Fe} \times \dfrac{\text{1 mol Fe}}{\text{55.845 g Fe}} = \text{0.003 5038 mol Fe}\\\\\text{Moles of O = 0.336 40} \times \dfrac{\text{1 mol O}}{\text{16.00 g O}} = \text{0.021 025 mol O}$

3. Calculate the molar ratios

Divide all moles by the smallest number of moles.

$\text{C: } \dfrac{0.052629}{0.003 5038}= 15.021\\\\\text{H: } \dfrac{0.073568}{0.003 5038} = 20.997\\\\\text{Fe: } \dfrac{0.003 5038}{0.003 5038} = 1\\\\\text{O: } \dfrac{0.021025}{0.003 5038} = 6.0006$

4. Round the ratios to the nearest integer

C:H:O:Fe = 15:21:1:6

5. Write the empirical formula

$\text{The empirical formula is } \boxed{\textbf{C$_{15}$H$_{21}$FeO$_{6}$}}$

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3 years ago