Hello)
1)CH3-CH(OH)-СН2-СН2-СН2-СН2-СН3---(H2SO4)--›CH3-CH=CH-CH2-CH2-CH2-CH3+H2O
2)2-methyl-l-cyclohexanol---(h2so4)--›CH2=C(CH3)-CH2-CH2-CH2-CH2-CH3+H2O
Answer : The amount left of leutium-176 will be, 2.10 g
Solution :
First we have to calculate the rate constant, we use the formula :
Now we have to calculate the amount left of the sample.
Expression for rate law for first order kinetics is given by :
where,
k = rate constant =
t = decay time =
a = initial amount of the sample = 16.8 g
a - x = amount left after decay process = ?
Now put all the given values in above equation, we get
Therefore, the amount left of leutium-176 will be, 2.10 g
I cant really help you but here is a few articles that may help you.
http://www.icr.org/article/do-bacteria-evolve-resistance-antibiotics/
https://www.ncbi.nlm.nih.gov/books/NBK45713/
http://www.windows2universe.org/cool_stuff/tour_evolution_9.html
http://evolution.berkeley.edu/evolibrary/news/080401_mrsa
http://evolution.berkeley.edu/evolibrary/article/_0/evoscales_03