Question

Consider the three displacement vectors

Answer 1

Answer:

Explanation:

$\overrightarrow{A} = 3\widehat{i}+3\widehat{j}$

$\overrightarrow{B} = \widehat{i}-4\widehat{j}$

$\overrightarrow{C} = -2\widehat{i}+5\widehat{j}$

(a)

$\overrightarrow{D} =\overrightarrow{A}+\overrightarrow{B}+\overrightarrow{C}$

$\overrightarrow{D} =\left ( 3+1-2 \right )\widehat{i} +\left ( 3-4+5 \right )\widehat{j}$

$\overrightarrow{D} =\left 2\widehat{i} +4\widehat{j}$

Magnitude of $\overrightarrow{D}$ = $\sqrt{2^{2}+4^{2}}$

                                                                     = 4.47 m

Let θ be the direction of vector D

$tan\theta =\frac{4}{2}$

θ = 63.44°

(b)

$\overrightarrow{E} = - \overrightarrow{A}-\overrightarrow{B}+\overrightarrow{C}$

$\overrightarrow{E} =\left ( - 3- 1 -2 \right )\widehat{i} +\left ( - 3 + 4+5 \right )\widehat{j}$

$\overrightarrow{E} =- \left 6\widehat{i} +6\widehat{j}$

Magnitude of $\overrightarrow{E}$ = $\sqrt{6^{2}+6^{2}}$

                                                                     = 8.485 m

Let θ be the direction of vector D

$tan\theta =\frac{6}{-6}$

θ = 135°