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4 years ago

9

What happens at the anode of an electrolytic cell?

1 answer:

Svetllana [295]4 years ago

4 0

The correct answer for the question that is being presented above is this one: "c. electrons are formed." The anode inside the electrolytic cell makes the <span>electrons formed. There is something happened inside the electrolytic cell that will make the electrons to form.</span>

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which type of relationship exists when a certain type of trees roots need a fungus present in order to grow normally

Afina-wow [57]

Judging on the fact that this is middle school physics, I would say that it is a beneficial relationship.

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3 years ago

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The intensity of light from a star (its brightness) is the power it outputs divided by the surface area over which it’s spread:

kow [346]

Answer:

$\frac{d_{1}}{d_{2}}=0.36$

Explanation:

1. We can find the temperature of each star using the Wien's Law. This law is given by:

$\lambda_{max}=\frac{b}{T}=\frac{2.9x10^{-3}[mK]}{T[K]}$ (1)

So, the temperature of the first and the second star will be:

$T_{1}=3866.7 K$

$T_{2}=6444.4 K$

Now the relation between the absolute luminosity and apparent brightness is given:

$L=l\cdot 4\pi r^{2}$ (2)

Where:

L is the absolute luminosity
l is the apparent brightness
r is the distance from us in light years

Now, we know that two stars have the same apparent brightness, in other words l₁ = l₂

If we use the equation (2) we have:

$\frac{L_{1}}{4\pi r_{1}^2}=\frac{L_{2}}{4\pi r_{2}^2}$

So the relative distance between both stars will be:

$\left(\frac{d_{1}}{d_{2}}\right)^{2}=\frac{L_{1}}{L_{2}}$ (3)

The Boltzmann Law says, $L=A\sigma T^{4}$ (4)

σ is the Boltzmann constant
A is the area
T is the temperature
L is the absolute luminosity

Let's put (4) in (3) for each star.

$\left(\frac{d_{1}}{d_{2}}\right)^{2}=\frac{A_{1}\sigma T_{1}^{4}}{A_{2}\sigma T_{2}^{4}}$

As we know both stars have the same size we can canceled out the areas.

$\left(\frac{d_{1}}{d_{2}}\right)^{2}=\frac{T_{1}^{4}}{T_{2}^{4}}$

$\frac{d_{1}}{d_{2}}=\sqrt{\frac{T_{1}^{4}}{T_{2}^{4}}}$

$\frac{d_{1}}{d_{2}}=\sqrt{\frac{T_{1}^{4}}{T_{2}^{4}}}$

$\frac{d_{1}}{d_{2}}=0.36$

I hope it helps!

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3 years ago

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cluponka [151]

Answer:

For 6 its D

For 7 its A

For 8 its C

For 9 I think its B but Im not sure

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3 years ago

An artillery shell is fired at a target 200 m above the ground. When the shell is 100 m in the air, it has a speed of 100 m/s. W

Marat540 [252]

Explanation:

Below is an attachment containing the solution.

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3 years ago

When you rub two balloons on your sleeve, does it have positive or negative?

igomit [66]

When you rub the balloons, it will take electrons away, which is negative. So, the balloons are negative

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3 years ago

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