Answer: momentum afterwards = 1040.4kgm/s
Explanation:
C) Staring At Someone's Body, Giving Them The “Once Over”
The most widely accepted theory about the universe is the big bang theory.
<h3>What is big bounce theory?</h3>
The Big Bounce theory refers to the universe that is expanding and contracting, move back and forth in a big-picture timeline. The Big Bang theory was happened about 13.8 billion years ago when the universe began as a tiny, dense, ball that exploded. Many astronomers use the Big Bang theory to show how the universe began. But what caused this explosion in the first thing that is still a mystery. It has passed through many stages, which can be considered cosmological theories. The flat Earth, the geocentric model, heliocentricity, galactic centricity, the Big Bang, and the Inflationary Big Bang. In the Big Bounce theory, the universe is expanding and contracting, seesawing back and forth in a massively big-picture timeline more specific theory called "Big Bounce" theory proposes that the universe could collapse to the state where it is first started and then initiate another Big Bang.
So we can conclude that The Big Bang theory says that the universe came into being from a single more than 13 billion years ago.
Learn more about theory here: brainly.com/question/11555274
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Answer:
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Explanation:sorry need answer
Answer:
1.6s
Explanation:
Given that A 1.20 kg solid ball of radius 40 cm rolls down a 5.20 m long incline of 25 degrees. Ignoring any loss due to friction,
To know how fast the ball will roll when it reaches the bottom of the incline, we need to calculate the acceleration at which it is rolling.
Since the frictional force is negligible, at the top of the incline plane, the potential energy = mgh
Where h = 5.2sin25
h = 2.2 m
P.E = 1.2 × 9.8 × 2.2
P.E = 25.84 j
At the bottom, K.E = P.E
1/2mv^2 = 25.84
Substitutes mass into the formula
1.2 × V^2 = 51.69
V^2 = 51.69/1.2
V^2 = 43.07
V = 6.56 m/s
Using the third equation of motion
V^2 = U^2 + 2as
Since the object started from rest,
U = 0
6.56^2 = 2 × a × 5.2
43.07 = 10.4a
a = 43.07/10.4
a = 4.14 m/s^2
Using the first equation of motion,
V = U + at
Where U = 0
6.56 = 4.14t
t = 6.56/4.14
t = 1.58s
Therefore, the time the ball rolls when it reaches the bottom of the incline is approximately 1.6s