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forsale [732]
3 years ago
8

Neither _____ nor _____ can be created or destroyed, but they can be changed from one to the other

Physics
2 answers:
monitta3 years ago
7 0

The answer is:

Matter & Energy

NEITHER MATTER NOR ENERGY CAN BE CREATED NOR DESTROYED BUT THEY CAN BE CHANGED FROM ONE FORM TO ANOTHER.

This is the law of energy created by Julius Lothar Meyer, a german chemist

He also created the first periodic table...

HOPE THIS HELPS!  :)

Viktor [21]3 years ago
3 0

Matter nor energy

hope this helps

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Please help i need an explanation
const2013 [10]

Answer:

--

Explanation:

All potential and kinetic energy is transferred into heat. Therefore keeping the law of conservation of energy valid. No energy is created nor destroyed only changing shape.

6 0
3 years ago
Question 5
Ksenya-84 [330]

Answer:

The force of the nail pushing in the opposite direction

5 0
3 years ago
How much thermal energy is created when a 3000 kg suv brakes to a stop from 20 m/s on a level road?
JulsSmile [24]

Answer:

b. 600,000 J

Explanation:

Applying the law of conservation of energy,

The thermal energy created = Kinetic energy of the suv.

Q' = 1/2(mv²)............... Equation 1

Where Q' = Thermal energy, m = mass of the suv, v = velocity of the suv.

From the question,

Given: m = 3000 kg, v = 20 m/s

Substitute these values into equation 1

Q' = 1/2(3000×20²)

Q' = 600000 J

Hence the right option is b. 600,000 J

5 0
3 years ago
The magnetic field 0.02 m from a wire is 0.1 t. what is the magnitude of the magnetic field 0.01 m from the same wire?
juin [17]

Answer:

0.2 T

Explanation:

3 0
3 years ago
Read 2 more answers
What will be the final temperature if a 4.00 g silver ring at 41.0◦C if it gives off 18.0 J of heat to the surroundings? The spe
Eduardwww [97]

Answer:

Final temperature, T_f=21.85^{\circ}

Explanation:

Given that,

Mass of silver ring, m = 4 g

Initial temperature, T_i=41^{\circ}C

Heat released, Q = -18 J (as heat is released)

Specific heat capacity of silver, c=0.235\ J/g\ C

To find,

Final temperature

Solution,

The expression for the specific heat is given by :

Q=mc\Delta T

Q=mc(T_f-T_i)

T_f=\dfrac{-Q}{mc}+T_i

T_f=\dfrac{-18}{4\times 0.235}+41

T_f=21.85^{\circ}

So, the final temperature of silver is 21.85 degrees Celsius.

5 0
3 years ago
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