Lesson 9: Please Help Me! NOTE: There Are 5 Questions!
1 answer:
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Hey Jackson!
-4x + 3y = 3
y = 2x + 1
Ok so what we need to do is solving y= 2x + 1 for y.
So let's start by using the substitution method :)
Substitute 2x + 1 for y in -4x + 3y = 3
-4x+ 3y = 3
-4x + 3(2x + 1) = 3
-4x + (3)(2x) + (3)(1) = 3
-4x + 6x + 3 = 3
2x + 3 = 3
Subtract 3 on both sides
2x + 3 - 3 = 3 - 3
2x = 0
x = 0/2
x = 0
So now since we find the number for x, we gonna use it to help us find the value for y.
To find y, we need to substitute 0 for x in y = 2x + 1
y = 2x + 1
y = 2(0) + 1
y = 0 + 1
y = 1
Thus,
The answer is: y = 1 and x = 0
How to graph?
You need to go on the thing where they put the numbers. y is located on top which has the positive numbers. So when you get there, make a line that comes from the top right side all the way to the bottom left sides. Remember that y = 1 so the line must pass through 1
I am not good with explanation. So I'll leave the graph down below then you'll see what I am talking about :)
Let me know if you have any questions. As always, it is my pleasure to help students like you!
-4x + 3y = 3
y = 2x + 1
Ok so what we need to do is solving y= 2x + 1 for y.
So let's start by using the substitution method :)
Substitute 2x + 1 for y in -4x + 3y = 3
-4x+ 3y = 3
-4x + 3(2x + 1) = 3
-4x + (3)(2x) + (3)(1) = 3
-4x + 6x + 3 = 3
2x + 3 = 3
Subtract 3 on both sides
2x + 3 - 3 = 3 - 3
2x = 0
x = 0/2
x = 0
So now since we find the number for x, we gonna use it to help us find the value for y.
To find y, we need to substitute 0 for x in y = 2x + 1
y = 2x + 1
y = 2(0) + 1
y = 0 + 1
y = 1
Thus,
The answer is: y = 1 and x = 0
How to graph?
You need to go on the thing where they put the numbers. y is located on top which has the positive numbers. So when you get there, make a line that comes from the top right side all the way to the bottom left sides. Remember that y = 1 so the line must pass through 1
I am not good with explanation. So I'll leave the graph down below then you'll see what I am talking about :)
Let me know if you have any questions. As always, it is my pleasure to help students like you!
Answer:
Step-by-step explanation:
The diagram of the right angle triangle is shown in the attached photo.
From the given right angle triangle,
AC represents the hypotenuse of the right angle triangle.
With m∠32 as the reference angle,
BC represents the adjacent side of the right angle triangle.
AB represents the opposite side of the right angle triangle.
To determine BC, we would apply
the Sine trigonometric ratio which is expressed as
Sin θ= opposite side/hypotenuse. Therefore, the expression used to find BC is
Sin 32 = BC/9
BC = 9Sin32
