Answer:
it is 2 1/2
Step-by-step explanation:
I hope this helps
Answer:
P and Q are two points on the line x-y+1=0 and are at a distant of 5 units from the origin. Find the area of triangle POQ.
Step-by-step explanation:
P and Q are the intersection points of
x-y+1 = 0 and the circle x^2 + y^2 = 25
sub y = x+1 into the circle
x^2 + (x+1)^2 = 25
x^2 + x^2 + 2x + 1 - 25 = 0
x^2 + x - 12 = 0
(x+4)(x-3) = 0
x = 3 or x = -4
y = 4 or y = -3
so P(3,4) and Q(-4,3) are our two points
Height of triangle.
h = |0 - 0 + 1|/√2 = 1/√2
PQ = √( (-7)^2 + 1^2) = √50 = 5√2
area POQ = (1/2)(1/√2)(5√2) = 5/2 square units
hope this helped
(1,1)
(2,3)
(0,-1)
(3,5)
(4,7)
it’s actually very simple, all you have to do is plug in whatever value you want for x and then solve the problem. once you have done that you put it in this format: (x,y)
for example, the first ordered pair that i told you: (1,1)
i got this by first deciding to use 1 as my x-value, then plugging it into the equation, so it was y=2•1-1. from there you just solve for y, which is very simple. make sure you remember order of operations though, or you could get it wrong! from that step i just put it in ordered pair format, or (x,y). this made my first ordered pair, which was (1,1). you can use the same steps for all ordered pairs you want to find. i hope this helps!
