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melamori03 [73]
3 years ago
7

Is the following relation a function? {(3, −2), (1, 2), (−1, −4), (−1, 2)}

Mathematics
2 answers:
Yanka [14]3 years ago
4 0

Answer: No, it is not a function.

Step-by-step explanation:

  • A function is a special kind of relation between two variables commonly x and y such that each x (input) value corresponds to a unique y(output) value.

The given relation:  {(3, −2), (1, 2), (−1, −4), (−1, 2)}

According to the above definition, the given relation is not a function because -1 corresponds to two different output values i.e. -4 and 2.

Hence, the given relation is not a function.

mel-nik [20]3 years ago
3 0

Answer:

<h2>It's not a function.</h2>

Step-by-step explanation:

A function is a process or a relation that associates each element x of a set X, to a single element y of another set Y.

We have:

{(3, -2), (1, 2), (-1, -4), (-1, 2)}

for x = -1 are two values of y = -4 and y = 2. Therefore this realtion is not a function.

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What is the value of x in the equation 4x+8y=40 , when y=0.8 ?
solniwko [45]

x = 8.4

Steps:

  1. Multiply the numbers: 4x + 6.4 =40
  2. Move the Constant to the right: 4x = 40 - 6.4
  3. Subtract the numbers: 4x = 33.6
  4. Divide 4 for both sides : 8.6
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4 years ago
Help can’t seem to figure out the base number?
fredd [130]

9514 1404 393

Answer:

  B = 6.65 in²

Step-by-step explanation:

The base area (B) is the area of the triangular base of the prism. You already know the sides of that triangle are 3, 5, and 7 inches. The figure shows the altitude to the side length 7 is 1.9 inches. The triangle area formula applies:

  A = 1/2bh

  A = 1/2(7 in)(1.9 in) = 6.65 in² . . . . area of one triangular base.

Then the area of one base is B = 6.65 in².

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The lateral area is the product of the perimeter and the height:

  LA = Ph = 15(12) = 180 . . . . square inches

The total surface area is the sum of the lateral area and the areas of the two bases.

  SA = LA + 2B

  SA = 180 in² + 2(6.65 in²) = 193.3 in²

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3 years ago
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ycow [4]

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4 years ago
In 2008, there were 507 children in Arizona out of 32,601 who were diagnosed with Autism Spectrum Disorder (ASD) ("Autism and de
Naily [24]

Answer:

z=\frac{0.0156-0.0114}{\sqrt{0.01554(1-0.01554)(\frac{1}{32601}+\frac{1}{88})}}=0.318    

p_v =P(Z>0.318)=0.375  

So the p value is a very high value and using the significance level provided \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona is not significantly higher than the national incident rate at 1% of significance.

Step-by-step explanation:

Data given and notation  

X_{1}=507 represent the number of children diagnosed with Autism Spectrum Disorder (ASD) in Arizona

n_{1}=32601 sample elected from arizona

\hat p_{1}=\frac{507}{32601} =0.0156 represent the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona

p_{2}=\frac{1}{88}= 0.0114 represent the proportion of children diagnosed with Autism Spectrum Disorder (ASD)  in the nation

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if that the incident of ASD is more in Arizona than nationally, the system of hypothesis are:

Null hypothesis:p_{1} \leq p_{2}  

Alternative hypothesis:p_{1} > p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{507+1}{32601 +88}=0.01554  

Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.0156-0.0114}{\sqrt{0.01554(1-0.01554)(\frac{1}{32601}+\frac{1}{88})}}=0.318    

Statistical decision

The significance level provided is \alpha=0.01, and we can calculate the p value for this test.    

Since is a one right sided test the p value would be:  

p_v =P(Z>0.318)=0.375  

So the p value is a very high value and using the significance level provided \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona is not significantly higher than the national incident rate at 1% of significance.

5 0
3 years ago
Which one is the correct answer?
xxMikexx [17]

Answer:

Step-by-step explanation: IDK

3 0
4 years ago
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