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2 years ago

I cant download the answers.

Mathematics

2 answers:

Fofino [41]2 years ago

7 0

Answer:

{-3, -2, -1}

Step-by-step explanation:

maks197457 [2]2 years ago

5 0

Answer:

add it then it will be easy than downloading

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Let ABC be a triangle such that AB=13 BC=14 and CA=15. D is a point on BC such that AD Bisects

Yuri [45]

Answer:

Area of triangle ADC is 54 square unit

Step-by-step explanation:

Here is the complete question:

Let ABC be a triangle such that AB=13, BC=14, and CA=15. D is a point on BC such that AD bisects angle A. Find the area of triangle ADC .

Step-by-step explanation:

Please see the attachment below for an illustrative diagram

Considering the diagram,

BC = BD + DC = 14

Let BD be $x$ ; hence, DC will be $14-x$

and AD be $y$

To, find the area of triangle ADC

Area of triangle ADC = $\frac{1}{2} (DC)(AD)$

= $\frac{1}{2}(14-x)(y)$

We will have to determine $x$ and $y$

First we will find the area of triangle ABC

The area of triangle ABC can be determined using the Heron's formula.

Given a triangle with a,b, and c

$Area =\sqrt{s(s-a)(s-b)(s-c)}$

Where $s = \frac{a+b+c}{2}$

For the given triangle ABC

Let $a$ = AB, $b$ = BC, and $c$ = CA

Hence, $a = 13, b= 14,$ and $c = 15$

∴ $s = \frac{13+14+15}{2} \\s= \frac{42}{2}\\s = 21$

Then,

Area of triangle ABC = $\sqrt{(21)(21-13)(21-14)(21-15)}$

Area of triangle ABC = $\sqrt{(21)(8)(7)(6)}$ = $\sqrt{7056}$

Area of triangle ABC = 84 square unit

Now, considering the diagram

Area of triangle ABC = Area of triangle ADB + Area of triangle ADC

Area of triangle ADB = $\frac{1}{2} (BD)(AD)$

Area of triangle ADB = $\frac{1}{2}(x)(y)$

Hence,

Area of triangle ABC = $\frac{1}{2}(x)(y)$ + $\frac{1}{2}(14-x)(y)$

84 = $\frac{1}{2}(x)(y)$ + $\frac{1}{2}(14-x)(y)$

∴ $84 = \frac{1}{2}(xy) + 7y - \frac{1}{2}(xy)$

$84 = 7y\\y = \frac{84}{7}$

∴ $y = 12$

Hence, $y =$ AD = 12

Now, we can find BD

Considering triangle ADB,

From Pythagorean theorem,

/AB/² = /AD/² + /BD/²

∴13² = 12² + /BD/²

/BD/² = 169 - 144

/BD/ = $\sqrt{25}$

/BD/ = 5

But, BD + DC = 14

Then, DC = 14 - BD = 14 - 5

BD = 9

Now, we can find the area of triangle ADC

Area of triangle ADC = $\frac{1}{2} (DC)(AD)$

Area of triangle ADC = $\frac{1}{2} (9)(12)$

Area of triangle ADC = 9 × 6

Area of triangle ADC = 54 square unit

Hence, Area of triangle ADC is 54 square unit.

5 0

3 years ago

Car rental company chargers it’s customers an initial fee of 30$ plus daily charge of 25$ to rent a car . Jacob has a budget of

nignag [31]

Answer:

Jacob can rent a car for 6 days with $20 left to spare.

Step-by-step explanation:

200 - 30 = 170

170 / 25 = 6.8

25 * 6 = 150

170 - 150 = 20

6 0

3 years ago

Read 2 more answers

What is the relationship between the 6s in the number 7,664

Xelga [282]

The answer to your question is 600 and 60

4 0

3 years ago

after flying at an altitude of 50 meters, a helicopter starts to descend when its ground distance from the landing pad is 11 kil

yarga [219]

Answer:

The angle of depression for the flight part is approximately 0.2604 degrees

Step-by-step explanation:

The given altitude at which the helicopter is flying = 50 meters

The horizontal distance of the helicopter from the helipad = 11 kilometers = 11,000 meters

The angle of depression = The angle of elevation = Arctan(Altitude/(Horizontal distance)

Therefore;

The angle of depression for the flight part = Arctan(50/(11,000)) ≈ 0.2604 degrees

8 0

2 years ago

A survey of 100 people in New York City, NY found that.

S_A_V [24]

Answer: 0.9

Step-by-step explanation:

$\mathrm{Total \ sample \ space \ $=100$} \\\mathrm{Event \ $A = \ taking \ subway \ each \ day}$$P(A)=0.85$$Event $B=$ taking taxi $\because P(B)=0.6$$$P(A \cap B)=0.55$$$

$\begin{aligned}P(A \cup B) & \Rightarrow \text { Person taking either taxi/subway } \\&=P(A)+P(B)-P(A \cap B) \\&=(0.85-0.555)+(0.6-0.55)-0.55 \\&=1.45-0.55\\&\bf{=0.9} \end{aligned}$

7 0

2 years ago