How do you do 2 step eqations
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Hi there!
f(x) = 2x + 6
Differentiating 2x = 2 (Power rule, dy/dx xⁿ = nxⁿ⁻¹)
Differentiating a constant always equals 0.
Thus:
f'(x) = 2
Hi there!
f(x) = 2x + 6
Differentiating 2x = 2 (Power rule, dy/dx xⁿ = nxⁿ⁻¹)
Differentiating a constant always equals 0.
Thus:
f'(x) = 2