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san4es73 [151]
3 years ago
13

If calcium carbonate (CaCO3) decomposes, what would the product of the reaction be?

Chemistry
2 answers:
NemiM [27]3 years ago
8 0

It was C) CaO on edg

LekaFEV [45]3 years ago
3 0

Answer:

C) CaO

Explanation:

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Mila [183]

Answer:A

Explanation:

Your muscular system is at work

6 0
2 years ago
What are nanochemicals and what are there uses?
NARA [144]

Nanochemicals can be defined as chemicals generated by using nanomaterials (materials that possess of size on nanometer dimensions). The nanochemicals are used in multiple different applications including chemical warfare, bicycle making, armor design and military weapons crafting. The most commonly used and observed nanochemicals are carbon nanotubes that are used a ton in industry for applications such as stronger materials (stronger bicycles).

Smart materials are exquisitely designed materials whose property(ies) can be modified with the use of an external stimulus such as temperature, stress, pH, and so on. Some examples of smart materials include shape memory materials, piezoelectric materials, ferrofluids, self-healing materials, and such. Applications involve memory pillows, memory based solar panels (for satellites), light sensitive glasses, and so on.

Specialized materials are made specifically to perform a specified task or function. Applications involve electronic equipment (high purity silicon & germanium), machine tools (high tungsten high carbon steel), dental filling (dental amalgam), and so on.

6 0
3 years ago
the standard change in Gibbs free energy is Δ????°′=7.53 kJ/molΔG°′=7.53 kJ/mol . Calculate Δ????ΔG for this reaction at 298 K29
Vera_Pavlovna [14]

Answer:

ΔG = 16.218 KJ/mol

Explanation:

  • dihydroxyacetone phosphate ↔ glyceraldehyde-3-phosphate
  • ΔG = ΔG° - RT Ln Q

∴ ΔG° = 7.53 KJ/mol * ( 1000 J / KJ ) = 7530 J/mol

∴  R = 8.314 J/K.mol

∴ T = 298 K

∴ Q = [glyceraldehyde-3-phosphate] / [dihydroxyacetone phosphate]

⇒ Q = 0.00300 / 0.100 = 0.03

⇒ ΔG = 7530J/mol - (( 8.314 J/K.mol) * ( 298 K ) * Ln ( 0.03 ))

⇒ ΔG = 16217.7496 J/mol ( 16.218 KJ/mol )

5 0
3 years ago
Concentrated sulfuric acid (18.3 M) has a density of 1.84 g/mL.
lianna [129]

The number of mole sulphuric acid in each mL of solution is 0.0183 mol/mL.

<h3>What is concentration?</h3>
  • Concentration in chemistry is calculated by dividing a constituent's abundance by the mixture's total volume.
  • Mass concentration, molar concentration, number concentration, and volume concentration are four different categories of mathematical description.  
  • Any type of chemical mixture can be referred to by the term "concentration," however solutes and solvents in solutions are most usually mentioned.
  • There are different types of molar (quantity) concentration, including normal concentration and osmotic concentration.
<h3>How is concentration determined?</h3>
  • Subtract the solute's mass from the total volume of the solution. Using m as the solute's mass and V as the total volume of the solution, write out the equation C = m/V.
  • To get the concentration of your solution, divide the mass and volume figures you discovered and plug them in.

Learn more about concentration here:

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6 0
2 years ago
Determine the elements present in sodium hydrogen carbonate ​
Ilia_Sergeevich [38]

Sodium, hydrogen, carbon, and oxygen

6 0
3 years ago
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