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riadik2000 [5.3K]
1 year ago
14

Wetlands are able to remove nutrients and chemicals from water as the water flows through the area. A developer is planning to d

estroy most of the wetlands near a bay. In three to five sentences, explain how destroying the wetlands would impact the bay’s water quality and ecosystem.
Chemistry
1 answer:
MakcuM [25]1 year ago
8 0

Destroying the wetlands will reduce the bay's water quality and vegetation will not grow effectively near bay as a result of which ecosystem will also destroy.

<h3>What is ecosystem?</h3>

All species and the physical environment with which they interact make up an ecosystem.

  • Nutrient cycles and energy flows bind these biotic and abiotic components together.
  • Photosynthesis brings energy into the system, which is absorbed into plant tissue.

As it is already mentioned that, water of the wetlands was carry nutrients which in turn was taken up by plants and vegetation, and if it will destroyed near a bay then the vegetation of that place will destroy as they will not get proper nutrients, which in turn also affects the ecosystem.

Hence destroying the wetlands will reduce the bay's water quality and vegetation will not grow effectively near bay as a result of which ecosystem will also destroy.

To know more about ecosystem, visit the below link:
brainly.com/question/2189549

#SPJ1

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A certain drug has a half-life in the body of 3.5h. Suppose a patient takes one 200.Mg pill at :500PM and another identical pill
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Answer:

The amount of drug left in his body at 7:00 pm is 315.7 mg.

Explanation:

First, we need to find the amount of drug in the body at 90 min by using the exponential decay equation:

N_{t} = N_{0}e^{-\lambda t}

Where:

λ: is the decay constant = ln(2)/t_{1/2}

t_{1/2}: is the half-life of the drug = 3.5 h

N(t): is the quantity of the drug at time t

N₀: is the initial quantity

After 90 min and before he takes the other 200 mg pill, we have:

N_{t} = 200e^{-\frac{ln(2)}{3.5 h}*90 min*\frac{1 h}{60 min}} = 148.6 mg

Now, at 7:00 pm we have:

t = 7:00 pm - (5:00 pm + 90 min) = 30 min

N_{t} = (200 + 148.6)e^{-\frac{ln(2)}{3.5 h}*30 min*\frac{1 h}{60 min}} = 315.7 mg    

Therefore, the amount of drug left in his body at 7:00 pm is 315.7 mg (from an initial amount of 400 mg).

I hope it helps you!

3 0
2 years ago
The nucleus of an atom contains at least one<br> proton.<br> True or false
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3 years ago
En un experimento hacemos reaccionar 12 g de carbono con 32 g de oxígeno para formar dióxido de carbono. Razona si podemos saber
max2010maxim [7]

Answer:

La masa de óxido de carbono iv formado es 44 g.

Explanation:

En esta pregunta, se nos pide calcular la masa de óxido de carbono iv formado a partir de la reacción de masas dadas de carbono y oxígeno.

En primer lugar, necesitamos escribir una ecuación química equilibrada.

C + O2 → CO2

De la ecuación, 1 mol de carbono reaccionó con 1 mol de oxígeno para dar 1 mol de óxido de carbono iv.

Ahora, si marca las masas en la pregunta, verá que corresponde a la masa atómica y la masa molar de la molécula de carbono y oxígeno, respectivamente. ¿Qué indica esto?

Como tenemos una relación molar de 1: 1 en todo momento, lo que esto significa es que la masa de óxido de carbono iv producida también es la misma que la masa molar de óxido de carbono iv.

Por lo tanto, procedemos a calcular la masa molar de óxido de carbono iv Esto es igual a 12 + 2 (16) = 12 + 32 = 44 g Por lo tanto, la masa de óxido de carbono iv formado es 44 g

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