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riadik2000 [5.3K]
2 years ago
14

Wetlands are able to remove nutrients and chemicals from water as the water flows through the area. A developer is planning to d

estroy most of the wetlands near a bay. In three to five sentences, explain how destroying the wetlands would impact the bay’s water quality and ecosystem.
Chemistry
1 answer:
MakcuM [25]2 years ago
8 0

Destroying the wetlands will reduce the bay's water quality and vegetation will not grow effectively near bay as a result of which ecosystem will also destroy.

<h3>What is ecosystem?</h3>

All species and the physical environment with which they interact make up an ecosystem.

  • Nutrient cycles and energy flows bind these biotic and abiotic components together.
  • Photosynthesis brings energy into the system, which is absorbed into plant tissue.

As it is already mentioned that, water of the wetlands was carry nutrients which in turn was taken up by plants and vegetation, and if it will destroyed near a bay then the vegetation of that place will destroy as they will not get proper nutrients, which in turn also affects the ecosystem.

Hence destroying the wetlands will reduce the bay's water quality and vegetation will not grow effectively near bay as a result of which ecosystem will also destroy.

To know more about ecosystem, visit the below link:
brainly.com/question/2189549

#SPJ1

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8 0
3 years ago
The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant. 2A(g)
monitta

Answer:

The value of the missing equilibrium constant ( of the first equation) is 1.72

Explanation:

First equation: 2A + B ↔ A2B   Kc = TO BE DETERMINED

 ⇒ The equilibrium expression for this equation is written as: [A2B]/[A]²[B]

Second equation: A2B + B ↔ A2B2   Kc= 16.4

⇒ The equilibrium expression is written as: [A2B2]/[A2B][B]

Third equation:  2A + 2B ↔ A2B2     Kc = 28.2

⇒ The equilibrium expression is written as: [A2B2]/ [A]²[B]²

If we add the first to the second equation

2A + B + B ↔ A2B2   the equilibrium constant Kc will be X(16.4)

But the sum of these 2 equations, is the same as the third equation ( 2A + 2B ↔ A2B2)   with Kc = 28.2

So this means: 28.2 = X(16.4)

or X = 28.2/16.4

X = 1.72

with X = Kc of the first equation

The value of the missing equilibrium constant ( of the first equation) is 1.72

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