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OleMash [197]
3 years ago
8

Dry ice goes directly from the solid phase to the gas phase. What phase

Chemistry
2 answers:
Marianna [84]3 years ago
8 0

Answer:

Sublimation is being represented.

Sublimation is the transition from solid to gas state

Hope this helps! Have a good day!

GalinKa [24]3 years ago
7 0

Answer:

Sublimation

Explanation:

Sublimation is when a solid turns into a gas

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Copper has a specific heat of 0.385 J/gºC.
Anna71 [15]

Answer:

The final temperature is 348.024°C.

Explanation:

Given data:

Specific heat of copper = 0.385 j/g.°C

Energy absorbed = 7.67 Kj (7.67×1000 = 7670 j)

Mass of copper = 62.0 g

Initial temperature T1 = 26.7°C

Final temperature T2 = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

Q = m.c. ΔT

7670 J = 62.0 g × 0.385  j/g °C ×( T2- 26.7 °C )

7670 J = 23.87 j.°C ×( T2- 26.7 °C )

7670 J / 23.87 j/°C = T2- 26.7 °C

T2- 26.7 °C = 321.324°C

T2 = 321.324°C + 26.7 °C

T2 = 348.024°C

The final temperature is 348.024°C.

6 0
3 years ago
How is the wavelength of an electromagnetic wave related to the energy of the wave?
Sauron [17]

The equation that relates both energy and wavelength is:

e=\frac{h*c}{lambda}

where e is the energy and lambda is the wavelength.

Therefore, as we can see from this equation, the energy of an electromagnetic wave is inversely related to the wavelength of the electromagnetic wave.

6 0
3 years ago
Read 2 more answers
The gas-phase reaction follows an elementary rate law and is to be carried out first in a PFR and then in a separate experiment
astraxan [27]

Answer:

The activation energy is =8.1\,kcal\,mol^{-1}

Explanation:

The gas phase reaction is as follows.

A \rightarrow B+C

The rate law of the reaction is as follows.

-r_{A}=kC_{A}

The reaction is carried out first in the plug flow reactor with feed as pure reactant.

From the given,

Volume "V" = 10dm^{3}

Temperature "T" = 300 K

Volumetric flow rate of the reaction v_{o}=5dm^{3}s

Conversion of the reaction "X" = 0.8

The rate constant of the reaction can be calculate by the following formua.

V= \frac{v_{0}}{k}[(1+\epsilon )ln(\frac{1}{1-X}-\epsilon X)]

Rearrange the formula is as follows.

k= \frac{v_{0}}{V}[(1+\epsilon )ln(\frac{1}{1-X}-\epsilon X)]............(1)

The feed has Pure A, mole fraction of A in feed y_{A_{o}} is 1.

\epsilon =y_{A_{o}}\delta

\delta = change in total number of moles per mole of A reacte.

=1(2-1)=1

Substitute the all given values in equation (1)

k=\frac{5m^{3}/s}{10dm^{3}}[(1+1)ln \frac{1}{1-0.8}-1 \times 0.8] = 1.2s^{-1}

Therefore, the rate constant in case of the plug flow reacor at 300K is1.2s^{-1}

The rate constant in case of the CSTR can be calculated by using the formula.

\frac{V}{v_{0}}= \frac{X(1+\epsilon X)}{k(1-X)}.............(2)

The feed has 50% A and 50%  inerts.

Hence, the mole fraction of A in feed y_{A_{o}} is 0.5

\epsilon =y_{A_{o}}\delta

\delta = change in total number of moles per mole of A reacted.

=0.5(2-1)=0.5

Substitute the all values in formula (2)

\frac{10dm^{3}}{5dm^{3}}=\frac{0.8(1+0.5(0.8))}{k(1-0.8)}=2.8s^{-1}

Therefore, the rate constant in case of CSTR comes out to be 2.8s^{-1}

The activation energy of the reaction can be calculated by using formula

k(T_{2})=k(T_{1})exp[\frac{E}{R}(\frac{1}{T_{1}}-\frac{1}{T_{2}})]

In the above reaction rate constant at the two different temperatures.

Rearrange the above formula is as follows.

E= R \times(\frac{T_{1}T_{2}}{T_{1}-T_{2}})ln\frac{k(T_{2})}{k(T_{1})}

Substitute the all values.

=1.987cal/molK(\frac{300K \times320K}{320K \times300K})ln \frac{2.8}{1.2}=8.081 \times10^{3}cal\,mol^{-1}

=8.1\,kcal\,mol^{-1}

Therefore, the activation energy is =8.1\,kcal\,mol^{-1}

8 0
3 years ago
What would be the molarity of a solution in which 0.56 mole of NaCl is dissolved in enough water to make 2.7 L of solution?
yan [13]

Answer:

Molarity = 0.21 M

Explanation:

Moles <em>solute </em>(mol) = Volume <em>solution</em> (L) x Molarity <em>solution </em>(M)

0.56 mol NaCl = 2.7 L x M

M = 0.2074074074

5 0
2 years ago
What would be the change in pressure in a sealed 10.0 l vessel due to the formation of n2 gas when the ammonium nitrite in 2.40
larisa86 [58]

The  change  in pressure in a sealed 10.0L vessel  is 5.28 atm

<u><em>calculation</em></u>

The pressure is calculated using the ideal gas equation

That is   P=n RT

where;

P (pressure)= ?

v( volume) = 10.0 L

n( number of moles)  which is calculated as below

<em>write the equation  for  decomposition  of   NH₄NO₂</em>

NH₄NO₂  →  N₂  +2H₂O

<em>Find the moles of NH₄NO₂</em>

 moles = molarity x volume in liters

= 2.40 l x 0.900 M =2.16 moles

<em>Use the mole ratio to determine the  moles of N₂</em>

that is from equation above  NH₄NO₂:N₂ is 1:1 therefore the moles of N₂ is also =2.16 moles

R(gas constant) =0.0821 l.atm/mol.K

T(temperature)  = 25° c  into kelvin = 25 +273 =298 K

make p the  subject of the formula  by diving both side  by  V

P = nRT/V

p ={ (2.16 moles x 0.0821 L.atm/mol.K  x 298 K) /10.0 L} = 5.28  atm.




3 0
3 years ago
Read 2 more answers
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