Atomic number = 42
Name = Molybdenum
Atomic symbol = Mo
Group number = VI(B)6
Mo = Metal
How to find all valves of Z=42?
Here, we are going to find out the name, symbol and group numbers element with the following Z value and their classification as a metal, metalloid, or nonmetal.
The atomic number of the element is 42
Therefore, the name of the element is Molybdenum
The atomic symbol of the element is Mo
The group number of is VI(B)6
Mo is a metal
Hence, the element is Molybdenum
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We first assume that this gas is an ideal gas where it follows the ideal gas equation. The said equation is expressed as: PV = nRT. From this equation, we can predict the changes in the pressure, volume and temperature. If the volume and the temperature of this gas is doubled, then the pressure still stays the same.
Answer:
280 g
Explanation:
Let's consider the decomposition of ammonium nitrate.
NH₄NO₃(s) ⇒ N₂(g) + 0.5 O₂(g) + 2 H₂O(g)
We can establish the following relations:
- The molar mass of NH₄NO₃ is 80.04 g/mol.
- The molar ratio of NH₄NO₃ to N₂ is 1:1.
- The molar mass of N₂ is 28.01 g/mol.
The mass of N₂ produced when 800 g of NH₄NO₃ react is:

The answer is 19.9 grams cadmium.
Assuming there was no heat leaked from the system, the heat q lost by cadmium would be equal to the heat gained by the water:
heat lost by cadmium = heat gained by the water
-qcadmium = qwater
Since q is equal to mcΔT, we can now calculate for the mass m of the cadmium sample:
-qcadmium = qwater
-(mcadmium)(0.850J/g°C)(38.6°C-98.0°C)) = 150.0g(4.18J/g°C)(38.6°C-37.0°C)
mcadmium = 19.9 grams
exactly 1 molecule of water is H2O just 1 is the answer