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Ad libitum [116K]
3 years ago
9

Use Boyle's Law to solve the following problem. A 400 mL sample of a gas is at 10

Chemistry
1 answer:
zubka84 [21]3 years ago
4 0

Answer:

v2 = 100 Ml OR 0.1 Liters

Explanation:

(400 Ml) (10 atm) = (v2) (40 atm)

4000 = 40v2

100 Ml = v2

Liters = ml / 1000

Liters = 100 / 1000

Liters = 0.1

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What is the oxidation number for s in s2o4?
hoa [83]
The oxidation number of O is -2 and there's 4 of them so the total is -8. Since it's a molecule the sum of the oxidation numbers of the atoms must equal 0. If 4 oxygen atoms have an oxidation number of -8 then the two S atoms must is +8 to equal 0 so the oxidation number of the S is 8/2 = +4
3 0
3 years ago
A 0.100 M oxalic acid, HO2CCO2H, solution is titrated with 0.100 M KOH. Calculate the pH when 25.00 mL of oxalic acid solution i
____ [38]

Answer:

pH = 4.09

Explanation:

molarity of oxalic acid in the solution

         = 0.1 x 25 / (25 + 35)

         = 0.0417 M

molarity of NaOH in the solution

          = 0.1 x 35 / (25 +35)

         = 0.0583 M

H2C2O4 + NaOH -------------------> NaHC2O4 + H2O

0.0417          0.0583                            0                0

0                      0.0166                         0.0417

now second acid -base titration  

NaHC2O4 + NaOH -------------------> Na2C2O4 + H2O

0.0417             0.0166                              0                0

0.0251                 0                                  0.0166         ---

now

pH = pKa2 + log [Na2C2O4 / NaHC2O4]

pH = 4.27 + log (0.0166 / 0.0251)

pH = 4.09

3 0
2 years ago
Is H2CO3 an Arrhenius acid?
Korolek [52]
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6 0
3 years ago
6. This part of Earth's atmosphere blocks the sun's harmful rays. (4 points)
Mrrafil [7]
Stratosphere:) hope this helped
7 0
2 years ago
Read 2 more answers
How many moles of KOH are required to produce 4.79 g K3PO4 according to the following reaction? 3KOH + H3PO4 -----> K3PO4 + 3
8_murik_8 [283]

Answer:

0.677 moles

Explanation:

Take the atomic mass of K = 39.1, O =16.0, P = 31.0

no. of moles = mass / molar mass

no. of moles of K3PO4 used = 4.79 / (39.1x3 + 31 + 16x4)

= 0.02256 mol

From the equation, the mole ratio of KOH : K3PO4 = 3 :1,

meaning every 3 moles of KOH used, produces 1 mole of K3PO4.

So, using this ratio, let the no. of moles of KOH required to be y.

\frac{3}{1} =\frac{y}{0.02256} \\

y = 0.02256 x3

y = 0.0677 mol

If you don't find exactly 0.677 moles as one of the options, go for the closest one. A very slight error may occur because of taking different significant figures of atomic masses when calculating.

5 0
3 years ago
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