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babymother [125]
3 years ago
11

The graph shows a 90° rotation. The matrix M such that, for any point (x, y), M(x, y) = (x', y') is

Mathematics
1 answer:
guapka [62]3 years ago
4 0

Answer:

A) \left[\begin{array}{cc}0&-1\\1&0\end{array}\right]

Step-by-step explanation:

The rotation matrix for a clockwise rotation through angle θ is given by ...

M=\left[\begin{array}{cc}\cos{(\theta)}&-\sin{(\theta)}\\\sin{(\theta)}&\cos{(\theta)}\end{array}\right]

When θ = 90°, the matrix becomes the one in choice A).

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The histograms below show the mass (in kilograms) of the offensive linemen on the University of Mount Union and the University o
Sedbober [7]

Answer:

Option C is correct.

None of the options is true.

Step-by-step explanation:

The histograms for the question is missing, so, it was obtained online and is attached to this solution of the question.

To check which statements are true, we first find the average using the midpoint technique.

The midpoint for each of the ranges is presented below

110 to 120 = 115

120 to 130 = 125

130 to 140 = 135

140 to 150 = 145

150 to 160 = 155

Sum of weights for Alabama linemen using the midpoint technique

= (125×4) + (135×8) + (145×4) + (155×2)

= 2470 kg

Average = (2470) ÷ (4+8+4+2)

= 137.22 kg

Sum of weights for Mount Union linemen

= (115×5) + (125×4) + (135×6) + (145×2)

= 2,175 kg

Average = (2,175) ÷ (5+4+6+2)

= 127.94 kg

So, it is evident that the average weight of Mount Union linemen isn't more than that of Alabama linemen.

Statement 2

All of the Alabama linemen have more mass than all of the Mount Union linemen

This is evidently not true because from the histogram, some linemen from Alabama have masses between 120 and 130, 130 and 140 & there are linemen from Mount Union that have masses between 130 and 140 & 140 and 150, so, it isn't right to say that all of the Alabama linemen have more mass than all of the Mount Union linemen.

So, none of the options is correct, option C.

Hope this Helps!!!

3 0
3 years ago
1. Keisha needs to make at least 28 costumes for the school play. Since she can make 4 costumes each week, Keisha plans to work
snow_lady [41]

Answer:

1. Let n represents the number of weeks she needs to make at least 28 costumes,

Since, she can make 4 costumes each week,

\implies n \geq \frac{28}{4}

\implies n \geq 7-----(1)

i.e. In number line closed circle on 7 and shaded right from 7.

2. If the maximum time taken by her is 10 weeks,

⇒ n ≤ 10 ----(2),

From equation (1) and (2),

7\leq n\leq 10

I.e. closed circle on both 7 and 10 and shaded right from 7 and shaded left from 10.

7 0
4 years ago
-2x+5y=30? Can someone show me the steps on how to put this into slope-intercept form?
chubhunter [2.5K]
Move the variable to the right 5y=30+2x Then decide both sides by 5 y=6+2/5x the reorder then using the communities property y=2/5x + 6 then that’s ur solution y=2/5x + 6
5 0
3 years ago
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8 0
3 years ago
a sphere and a right cylinder have the same radius and volume. the cylinder has a height of 8 feet. find the radius.​
lakkis [162]

Answer:

Step-by-step explanation:

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