9514 1404 393
Answer:
- red division: 6 teams
- blue division: 5 teams
Step-by-step explanation:
We can let r and b represent the numbers of teams in the red and blue divisions, respectively. The total number of goals scored in each division will be the average for that division times the number of teams in that division.
r - b = 1 . . . . . . there is 1 more red team than blue
4.5r +4.2b = 48 . . . . . . total goals scored per week
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Solving by substitution, we have ...
r = b +1
4.5(b +1) +4.2b = 48 . . . . substitute for r
8.7b +4.5 = 48 . . . . . . . . simplify
8.7b = 43.5 . . . . . . . . . . subtract 4.5
b = 43.5/8.7 = 5 . . . . . divide by 8.7
r = b +1 = 6 . . . . . . . . . find r
There are 6 red teams and 5 blue teams.
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<em>Additional comment</em>
The basic idea is that you make an equation for each relation given in the problem statement. For a problem like this, you do need to have an understanding of how the average number of goals would be calculated and how that relates to the total goals.
Yes because 0 and 4 dont equal 10 and 20 and 40 dont equal 100. So no and 40 + 23 = 63.
Answer:
k = -1/240
Step-by-step explanation:
to evaluate the value of k in the expression 1/3k+80=1/2k+120
we have
1/3k+80=1/2k+120
collect the like terms for easy evaluation
1/3k - 1/2k = 120 -80
1/3k - 1/2k = 40
find the lcm
2 - 3/6k = 40
-1/ 6k = 40
cross multiply
6k x 40 = -1
240k = -1
divide both sides by 240
240k/240 = -1/ 240
k = -1/240
therefore the value of k in the expression 1/3k+80=1/2k+120 is equals to -1/240
