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lana66690 [7]
3 years ago
13

In a geometric sequence, a2=108 and as 256. Write the explicit formula for this sequence.

Mathematics
2 answers:
torisob [31]3 years ago
8 0

Answer:

The first choice is correct.

Step-by-step explanation:

First work out the common ratio r:-

a2 = a1r and a5 = a1 r^4

So r^3 = a1r^4 / a1r = 256/ 108

r = cube root (256/-108) =  4/3

So the explicit formula is 108(4/3)^(n-1)

mariarad [96]3 years ago
4 0

Answer:

C. 81[-4/3]^n-1

Step-by-step explanation:

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An experimenter studies vision in low light by
Mariulka [41]

Answer:

Independent variable- time spent in the dark room

Dependent variable - number of objects correctly identified

Conditions of the experiment- low light environment and lighted environments

Scores from the independent variable are used to construct the frequency distribution

Step-by-step explanation:

The independent variable is the factor that is being manipulated in an experiment and this time it is the time spent in a darkened room.

The dependent variable is the response variable, in this case, the number of objects correctly identified.

The experimental conditions involved bringing people from a lighted area into a darkened room.

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2 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
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