Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
sq. units.
Answer:
x = 100√3
Step-by-step explanation:
tan(30º) = x/300
x = 300 tan(30º)
x = 300/√3
x = 100√3
Step-by-step explanation:
x -2 -1 2 7
y -6 -6 -2 3
All y are in under root
Step-by-step explanation:
9x2+5x4
= 18 + 20
= 38
the answer is 38
Answer:14
Step-by-step explanation: