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3 years ago

I will give brainliest

Mathematics

1 answer:

arsen [322]3 years ago

8 0

Answer:

The first graph represents y<2x-3

For this use some values for x e.g

X= 2 2(2)-3=y=1

So when x is 2 y is 1 so search for the graph that crosses the coordinate (2,1)

Which is graph A

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4/6x2/3 simplified and in fraction form

Kaylis [27]

Answer:

onvert 234 2 3 4 to an improper fraction. ... Divide each term by −6 - 6 and simplify. ... The result can be shown in multiple forms.

Step-by-step explanation:

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3 years ago

What word is synonymous for take-home pay

mash [69]

Answer:

net pay

Step-by-step explanation:

"Net" refers to what you get to keep after taxes or any fees,

"Gross" is your total before taxes and fees

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3 years ago

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Lin and her brother each created a scale drawing of the backyard, but at different scales. Lin used a scale of 1 inch to 1 foot.

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3 years ago

Sove for y 3 y + 13 equals 5 y - 5

Papessa [141]

If you could send an image that is clearer I will be able to help you more, but for what we have: 3y+13=5y-5, the answer would be 2y=18 (after doing all your algebra). Then you would divide both sides by 2 and get y=9. After this you can plug in 9 for every y and find the angles/measures of all sides!
Hope this helped, and if you need any further assistance, please let me know!

5 0

3 years ago

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A recent study suggested that 70% of all eligible voters will vote in the next presidential election. Suppose 20 eligible voters

natita [175]

Answer:

0.0479 = 4.79% probability that fewer than 11 of them will vote

Step-by-step explanation:

For each voter, there are only two possible outcomes. Either they will vote, or they will not. The probability of a voter voting is independent of any other voter, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

70% of all eligible voters will vote in the next presidential election.

This means that $p = 0.7$

20 eligible voters were randomly selected from the population of all eligible voters.

This means that $n = 20$

What is the probability that fewer than 11 of them will vote?

This is:

$P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{20,10}.(0.7)^{10}.(0.3)^{10} = 0.0308$

$P(X = 9) = C_{20,9}.(0.7)^{9}.(0.3)^{11} = 0.0120$

$P(X = 8) = C_{20,8}.(0.7)^{8}.(0.3)^{12} = 0.0039$

$P(X = 7) = C_{20,7}.(0.7)^{7}.(0.3)^{13} = 0.0010$

$P(X = 6) = C_{20,10}.(0.7)^{6}.(0.3)^{12} = 0.0002$

$P(X = 5) = C_{20,5}.(0.7)^{5}.(0.3)^{15} \approx 0$

The probability of 5 or less voting is very close to 0, so they will not affect the outcome. Then

$P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0) = 0.0308 + 0.0120 + 0.0039 + 0.0010 + 0.0002 = 0.0479$

0.0479 = 4.79% probability that fewer than 11 of them will vote

8 0

3 years ago

I will give brainliest ​

I will give brainliest