3 years ago

If the average of 12 numbers is 14 and the average of 4 of those numbers is 18, what is the average of the other eight numbers?

1 answer:

7 0

(8 + X + Y)/3 = 12

multiply both sides of the equation by 3 to get 8 + X + Y = 36

subtract 8 from both sides of the equation to get X + Y = 28

So, the sum of the 2 missing numbers is 28

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Vladimir79 [104]

Answer:

b=i* $\sqrt{\frac{59}{11} }$ or -i* $\sqrt{\frac{59}{11} }$

Step-by-step explanation:

11b^2-9=-68

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b^2=-59/11

b=i* $\sqrt{\frac{59}{11} }$ or -i* $\sqrt{\frac{59}{11} }$

"i" in this case is an imaginary number, equal to $\sqrt{-1\\}$

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SVEN [57.7K]

The first one is 154

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