The medians of a triangle intersect at a point called the
1 answer:
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Answer:
2
Step-by-step explanation:
Since triangles ABC and ADE are similar by AA (they share angle A and a right angle), their ratio of sides must be equal. Therefore:
Multiply both sides by 2:
Multiply both sides by x+2:
Subtract 2 from both sides:
Hope this helps!
Answer:
a) 7a/8; b) 5a/8
Step-by-step explanation:
Given:
AP = 2PQ = 2QB
Calculations:
1. A to the midpoint of QB
a = AP + PQ + QB
If 2PQ = 2QB.
PQ = QB and
AP = 2PQ
∴ a = 2PQ + 2PQ = 4PQ
PQ = a/4
AP = 2PQ = a/2
Let M be the midpoint of QB.
AM = AP + PQ + QM
= a/2 + a/4 + a/8
= 7a/8
2. Midpoints of AP and QB
Let N be the midpoint of AP
NM = NP + PQ + QM
= a/4 +a/4 + a/8 =
= 5a/8
