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jeka57 [31]
3 years ago
15

A cross-country skier reaches the 3-km mark of a race in 15 min and the 12-km mark 45 min later. Find the speed of the skier.

Mathematics
1 answer:
musickatia [10]3 years ago
4 0

Answer:

3 km every 15 mins

step-by-step explanation:

3*4==12

15+15+15= 45

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60/30 in simplistic form<br><br><br> Need answer quick!!!!!!!!!
makkiz [27]

Answer:

2

Step-by-step explanation:

60/30 is 2

HOpe this helps :D

PLz mark brainliest if correct :D

3 0
3 years ago
Problem 2
Sever21 [200]

Answer:

4.23 x 10 to the 4, 2 x 10 to the 3, 9.2 x 10 to the 6, 4 x 10 to the 3, 8 x 10 to the 7, and 3.2 x 10 to the 10.

Step-by-step explanation:

I will explain in the comments to this response

5 0
2 years ago
PLEASE HELP FAST
skad [1K]

Answer:

The unit vector u is (-5/√29) i - (2/√29) j

Step-by-step explanation:

* Lets revise the meaning of unit vector

- The unit vector is the vector ÷ the magnitude of the vector

- If the vector w = xi + yj

- Its magnitude IwI = √(x² + y²) ⇒ the length of the vector w

- The unit vector u in the direction of w is u = w/IwI

- The unit vector u = (xi + yj)/√(x² + y²)

- The unit vector u = [x/√(x² + y²)] i + [y/√(x² + y²)] j

* Now lets solve the problem

∵ v = -5i - 2j

∴ IvI = √[(-5)² +(-2)²] = √[25 + 4] = √29

- The unit vector u = v/IvI

∴ u = (-5i - 2j)/√29 ⇒ spilt the terms

∴ u = (-5/√29) i - (2/√29) j

* The unit vector u is (-5/√29) i - (2/√29) j

8 0
3 years ago
Find an equation of the tangent line to the curve at the given point. y = x + tan(x) at (pi, pi)
S_A_V [24]
<span>Differentiating :

y' = 1 + sec^2(x),
</span><span>
cosπ=−1</span><span>

plug in pi = -1 ,for x:

1 + sec^2(pi) = 1 +  (-1)^2 
                      = 2</span>
8 0
3 years ago
Explain number 2 &amp; 3 please
VLD [36.1K]
1. 3x - 2y = 0 => y = 3/2x
4x + 2y = 14<=> 4x + 2*(3/2x) = 14<=> 7x = 14<=> x = 2 & y = 3
2.3p + q = 7=> q = 7 - 3p
2p - 2q = -6<=> 2p - 2*(7-3p) = -6<=> 2p - 14 + 6p = -6<=> 8p = -6 + 14 = 8<=> p = 1 & q = 4
3.3x - 2y = 1=> x = (1+2y)/3
8x + 3y = 2<=> 8*(1+2y)/3 + 3y = 2<=> 8*(1+2y)/3 - 2 = -3y<=> 3*(8*(1+2y)/3 - 2) = -3*(3y)<=> 8*(1+2y) - 6 = -9y<=> 8 + 16y - 6 = -9y<=> 2 = -25y<=> y = -2/25 & x = 7/25
7 0
3 years ago
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