since Joe catches for fish today Melissa sketches to fish the amount of Joe's Fish is always greater Joe's Fish is also always t
wice as much as melissa's fish. Today , both melissa and joe have no fish. They both go fishing each day. Melisa catches 2 fish each day. Joe catches 4 fish each day. How many fish do they have after each of the five days? Make a graph of the number of fish. Plot the points on a coordinate plane and make a line graph, and then interpret the graph
The first thing you should do for this case is a function that suits the context of the problem. Let: x: number of days. y: number of fish trapped by melissa and Joe. The generic equation of the line is: y = mx + b Melisa catches 2 fish each day. Joe catches 4 fish each day. So: m = 6 Today, both melissa and joe have no fish. So: b = 0 In this case we have: y = 6x Looking at the graph we see that by day five, both have 30 fish. answer f (x) = 6x f (5) = 30
Use the formula: y = a(1 + r)^t a is the initial amount r is the percent of interest in decimal form t is the time in years y is the money after t years
Substitute the values given in the problem into the equation: 400(1+0.02)^20 Use a calculator or solve manually Around 594.38