since Joe catches for fish today Melissa sketches to fish the amount of Joe's Fish is always greater Joe's Fish is also always t
wice as much as melissa's fish. Today , both melissa and joe have no fish. They both go fishing each day. Melisa catches 2 fish each day. Joe catches 4 fish each day. How many fish do they have after each of the five days? Make a graph of the number of fish. Plot the points on a coordinate plane and make a line graph, and then interpret the graph
1 answer:
The first thing you should do for this case is a function that suits the context of the problem.
Let:
x: number of days.
y: number of fish trapped by melissa and Joe.
The generic equation of the line is:
y = mx + b
Melisa catches 2 fish each day. Joe catches 4 fish each day. So:
m = 6
Today, both melissa and joe have no fish. So:
b = 0
In this case we have:
y = 6x
Looking at the graph we see that by day five, both have 30 fish.
answer
f (x) = 6x
f (5) = 30
Let:
x: number of days.
y: number of fish trapped by melissa and Joe.
The generic equation of the line is:
y = mx + b
Melisa catches 2 fish each day. Joe catches 4 fish each day. So:
m = 6
Today, both melissa and joe have no fish. So:
b = 0
In this case we have:
y = 6x
Looking at the graph we see that by day five, both have 30 fish.
answer
f (x) = 6x
f (5) = 30
You might be interested in