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3 years ago

What is the area of the front of the rectangular prism?

Mathematics

1 answer:

iVinArrow [24]3 years ago

7 0

Answer:

Area = 28 cm² (check the attached diagram for better clarity)

Step-by-step explanation:

The question is incomplete but let's see a similar example

The front of a rectangular pyramid can refer to either one of two possibilities: it could be either the side that has the breadth and the height or the side that has the length and the height. In this case, we were given the formula for calculating the area of the front face of this rectangular prism as the product of breadth and height

Mathematically,

A = bh

From the attached diagram, we will see the properties of the rectangular prism as:

length = 5 cm, breadth = 4 cm, height = 7 cm

To calculate for the front face, we use A = bh,

⇒ A = 4 * 7 = 28 cm²

Example 2

If the breadth of the rectangular prism is 2 cm and the height is 3 cm, we have:

A = 2 * 3 = 6 cm²

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Thickness measurement ancient prehistoric Native American Pot Shards discovered in Hopi Village are approximately normally distr

beks73 [17]

Answer:

a) $P(X$

And we can find this probability using the normal standard table and we got:

$P(z$

b) $P(X>7)=P(\frac{X-\mu}{\sigma}>\frac{7-\mu}{\sigma})=P(Z>\frac{7-5.1}{0.9})=P(z>2.11)$

And we can find this probability using the complement rule and the normal standard table and we got:

$P(z>2.11)=1-P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(5.1,0.9)$

Where $\mu=5.1$ and $\sigma=0.9$

Part a

We are interested on this probability

$P(X$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X$

And we can find this probability using the normal standard table and we got:

$P(z$

Part b

We are interested on this probability

$P(X>7)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>7)=P(\frac{X-\mu}{\sigma}>\frac{7-\mu}{\sigma})=P(Z>\frac{7-5.1}{0.9})=P(z>2.11)$

And we can find this probability using the complement rule and the normal standard table and we got:

$P(z>2.11)=1-P(Z$

4 0

3 years ago

Point F(-17,8) is rotated 180° about the origin what are the coordinates of image f?

dlinn [17]

Answer:

F'(17, - 8 )

Step-by-step explanation:

Under a rotation about the origin of 180°

a point (x, y ) → (- x, - y ), thus

F(- 17, 8 ) → F'(17, - 8 )

5 0

3 years ago

The South Coast Air Basin (Los Angeles, Orange, and San Bernardino counties) does not meet the air quality standards for carbon

Archy [21]

Answer:

0.2225 gr/mile

Step-by-step explanation:

Let's work out first the amount of CO sent out in 1990.

The population we estimated in 12.5 million people with a total of driven miles per year of about

12.5 million*8,700 = 108,750 million miles.

With an CO emission factor of 0.9 g per mile, we would have a total of CO emitted rounding 0.9*180,750 = 97,875 million grams

Now, we must estimate the population for 2020.

Since we are assuming an exponential growth, the population in year t is given by a function

$\bf P(t)= Ce^{kt}$

where C and k are constants to be determined.

We can take 1980 as year 0. This way calculations are lighter. 1990 is year 10 and 2020 is year 20.

So P(0) = 10.3 and C=10.3

So far we have

$\bf P(t)= 10.3e^{kt}$

Given that P(10)=12.5

$\bf 10.3e^{k*10}=12.5\rightarrow e^{10k}=\frac{12.5}{10.3}=1.21359\rightarrow \\10k=log(1.21359)\rightarrow k=0.01936$

And the function that models the population growth is

$\bf P(t)= 10.3e^{0.01936t}$

We need P(20)

$\bf P(20)= 10.3e^{0.01936*20}=10.3e^{0.38717}=15.17\;million$

If the miles driven per person per year remains constant at 8700 mi/yr.person, then we have a total miles driven of

15.17*8,700=131,979 million miles, so the CO emitted would be 0.9*131,979=118,781.1 million grams.

The 30% of the CO sent out in 1990 is 0.3*97,875=29,362.5 million grams.

We must reduce 118,781.1 down to 29,362.5

Hence the new CO emission factor would be

29,362.5/131,979 = 0.2225 gr/mile

6 0

3 years ago

How many sides does a regular polygon have with one central of 18 degrees?

Natalka [10]

All of the centra angles in a regular polygon must add up to 360 degrees. Also, because you're told that it is a regular polygon, the "regular" indicates that all of the central angles will be the same. Divide 360 degrees by 18 degrees to get the number of central angles, which is the same as the number of sides. 360/18 = 20. Therefore, the polygon has 20 sides. Hope that helps!

7 0

3 years ago

6 9/10 x 20/21<br> Simplify your answer completely and change to a mixed number.

Sidana [21]

Answer:

$6\frac{4}{7}$