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Trava [24]
3 years ago
12

I have a geometry test I’m gonna fail. If you know any of these answers please put the number of the question,than the answer. I

t would help so much. I’m so stressed.

Mathematics
1 answer:
blsea [12.9K]3 years ago
3 0

Answer:

Step-by-step explanation:

20) Angles 1 and 2 are supplementary angles( sum of angle 1 and angle 2 is 180 degrees)

21) Angles 1 and 2 are supplementary angles( sum of angle 1 and angle 2 is 180 degrees)

22) Angle TUW + Angle WUV =Angle TUV

Therefore

(7x-9) + (5x - 11) = (9x+1)

7x-9 + 5x - 11 = 9x+1

7x +5x-9x =1 + 11 + 9

3x = 21

x = 21/3= 7

23) GEF - 13 = 5DEG

and DEF = 149 degrees

GEF = 5DEG + 13

Sum of angles (GEF + DEG)=DEF

Therefore,

DEG + 5DEG - 13 = 149

6DEG = 149 + 13 = 162

DEG = 162/6 = 27

GEF = 5DEG = 27 × 5 =135

24) 7x - 1 + 6x -1 = 180(sum of angles in a straight line)

13x-2 = 180

13x = 180+2 = 182

x = 182/13 = 14

25) 5x + 4 + 8x - 7 = 180( sum of supplementary angles is 180)

13x = 180+7-4= 183

x = 183/13 = 14.08

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B. 97%

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100 - 2.4 = 97.6

(2.4 is amount of data we are not using)

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3 years ago
1. Writing an equation for an exponential function by
Naya [18.7K]

Answer: 1) t(n)=0.6(2)^n

2) f(x)=10(5)^x

Step-by-step explanation:

1) Let the function that shows the thickness of the paper after n folds,

t(n) = ab^n         ---------(1)

Since, According to the question,

Initially the thickness of the paper = 0.6

That is, at n = 0, t(0) = 0.6

By equation (1),

0.6 = a(b)^0\implies 0.6 = a

Hence the function that shows the given situation,

t(n) = 0.6 b^n       -----------(2)

Again when we fold the paper the thickness of the paper will be doubled.

Thus, at n = 1, t(1) = 1.2

By equation (2),

1.2 = 0.6 b^1\implies 2 = b

Thus, the complete function is,

t(n) = 0.6 (2)^n    

2) Let the function that is passing through the points (-2, 2/5) and (-1,2),

f(x) = ab^x         ---------(1)

For f(x) = 2, x = -1

By equation (1),

2= ab^{-1}       ---------(2)

Also, For f(x) = 2/5, x = -2

Again, By equation (1),

\frac{2}{5}= a(b)^{-2}

\implies \frac{2}{5}=ab^{-1}b^{-1}=2b^{-1}

\implies \frac{2}{5}=\frac{2}{b}

\implies 2b=10

\implies b = 5

By substituting this value in equation (2),

We get, a = 10

Hence, from equation (1), the function that is passing through the points (-2, 2/5) and (-1,2),

f(x) = 10(5)^x

5 0
3 years ago
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