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bezimeni [28]
3 years ago
14

45 POINTS PLEASE HELP ME!!!! You roll two standard number cubes. What is the probability that the sum is odd, given than one of

the number cubes shows a 4?
Mathematics
1 answer:
Murljashka [212]3 years ago
8 0

Answer:

6/11

Step-by-step explanation:

We are not told which number cube shows a 4; it can be the first one or the second one.

If the first number cube is a 4, this gives us the options of:

4 and 1; 4 and 2; 4 and 3; 4 and 4; 4 and 5; 4 and 6.

However if the second number cube is a 4, this gives us

1 and 4; 2 and 4; 3 and 4; 4 and 4; 5 and 4; 6 and 4.

We cannot count "4 and 4" twice; this leaves us with 11 total possibilities.

Out of these 11, only the sum of 4 and an odd number will be odd:

1 and 4; 3 and 4; 5 and 4; 4 and 1; 4 and 3; 4 and 5.

There are 6 ways to have an odd sum out of 11 total possibilities; this gives us a probability of 6/11.

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Answer:

Step-by-step explanation:

(6e-3f-3/4) contains two terms which do not involve fractions and one fractional term (3/4).

We can safely remove the parentheses.  Then:

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That is "an equivalent expression."

We could go further and create one equivalent fraction.  Multiply the first two terms by 4/4, obtaining:

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