F(2)=4+10-8=6; f(6)=36+30-8=58. Average rate of change is (58-6)/(6-2)=52/4=13
Answer:
24
Step-by-step explanation:
what is the smallest number which is a multiple of both 8 and 12? so, an multiple of 8 must have 2 as a factor at least 3 times. Similarly, multiples of 12 have at least two 2's and one 3. so we need 2x2x2x3 or 24 if every factor is to be included.
I'm not the best at explaining but you can search google to get the better Idea.
(btw this is for the fist question)
![\bf tan(x^o)=1.11\impliedby \textit{taking }tan^{-1}\textit{ to both sides} \\\\\\ tan^{-1}[tan(x^o)]=tan^{-1}(1.11)\implies \measuredangle x=tan^{-1}(1.11)](https://tex.z-dn.net/?f=%5Cbf%20tan%28x%5Eo%29%3D1.11%5Cimpliedby%20%5Ctextit%7Btaking%20%7Dtan%5E%7B-1%7D%5Ctextit%7B%20to%20both%20sides%7D%0A%5C%5C%5C%5C%5C%5C%0Atan%5E%7B-1%7D%5Btan%28x%5Eo%29%5D%3Dtan%5E%7B-1%7D%281.11%29%5Cimplies%20%5Cmeasuredangle%20x%3Dtan%5E%7B-1%7D%281.11%29)
plug that in your calculator, make sure the calculator is in Degree mode
Answer to Problem 1: 5√3
Answer to Problem 2: 21√5
First, subtract k from both sides. That means c - k is in the left side and 3x is on the right. Then, divide by 3 on both sides. So, the answer is x = (c - k) / 3.
