Answer:
-8/15
Step-by-step explanation:
(1/15)-(3/3)*(3/5)= (1/15)-(9/15)=(1-9)/15=-8/15
Answer:
75.44 Square Inches
Step-by-step explanation:
The diagram of the problem is produced and attached.
To determine the area of the cleaned sector:
Let the radius of the larger sector be R
Let the radius of the smaller sector be r
Area of the larger sector ![=\frac{\theta}{360}X\pi R^2](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Ctheta%7D%7B360%7DX%5Cpi%20R%5E2)
Area of the smaller sector ![=\frac{\theta}{360}X\pi r^2](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Ctheta%7D%7B360%7DX%5Cpi%20r%5E2)
Area of shaded part =Area of the larger sector-Area of the smaller sector
![=\frac{\theta}{360}X\pi R^2-\frac{\theta}{360}X\pi r^2\\=\frac{\theta \pi}{360}X (R^2- r^2)](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Ctheta%7D%7B360%7DX%5Cpi%20R%5E2-%5Cfrac%7B%5Ctheta%7D%7B360%7DX%5Cpi%20r%5E2%5C%5C%3D%5Cfrac%7B%5Ctheta%20%5Cpi%7D%7B360%7DX%20%28R%5E2-%20r%5E2%29)
From the diagram, R=10 Inch, r=10-7=3 Inch, ![\theta=95^\circ](https://tex.z-dn.net/?f=%5Ctheta%3D95%5E%5Ccirc)
Therefore, Area of the sector cleaned
![=\frac{95 \pi}{360}X (10^2- 3^2)\\=75.44$ Square Inches](https://tex.z-dn.net/?f=%3D%5Cfrac%7B95%20%5Cpi%7D%7B360%7DX%20%2810%5E2-%203%5E2%29%5C%5C%3D75.44%24%20Square%20Inches)
Answer:
C both
Step-by-step explanation:
There is a graph
The fraction is in simplest form when the GCF of the numerator and denominator is 1.
For example, 1/2 is in simplest forms, but 2/4 isn't
The number of people being served went from 6 to 24, so the serving quadrupled.
So multiply 2.5 by 4 and you get 10 pounds of apples.