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Xelga [282]
2 years ago
13

Help please I will give you the brainliest

Mathematics
1 answer:
Komok [63]2 years ago
6 0

Answer:

its the first one and here is some advice go to the website m a t h w a y and enter the equation and click graph!

Step-by-step explanation:

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2. Rachel makes cranberry almond cookies. The number of cups of cranberries and the number of cups of almonds are shown in the t
Veronika [31]

Answer:

Step-by-step explanation:

By 2 for the first one.      And for 2 they skip counting by 6

7 0
3 years ago
Pleae help thanks a bunch
zloy xaker [14]
Hello!

You use the Pythagorean theorem to solve this

a^{2} + b^{2} = c^{2}

Put in the values it tells you to

a^{2} + 4.4^{2} = 5.5^{2}

Square the numbers

a^{2} + 19.36 = 30.25

Subtract 19.36 from both sides

a^{2} = 10.89

Take the square root of both sides

a = 3.3

The answer is 3.3

Hope this helps!
8 0
2 years ago
Distance
Slav-nsk [51]

Answer: 28 km

Step-by-step explanation: For the first 25 minutes, he drove 60 km/h. Since there is 60 minutes in an hour, we know that he drove 25 km. The rest of the journey is 15 minutes. 15 minutes is 1/4 of an hour, so get 1/4 of 12 km/h. This would be 3 km. Add 25 km and 3 km. The distance between the 2 malls is 28 km.

5 0
3 years ago
F=e−yi−xe−yj is conservative. find a scalar potential f and evaluate the line integral over any smooth path c connecting a(0,0)
Alexxx [7]
If \mathbf F is conservative, then there is a scalar function f such that

\nabla f(x,y)=\mathbf F(x,y)\iff\dfrac{\partial f}{\partial x}\,\mathbf i+\dfrac{\partial f}{\partial y}\,\mathbf j=e^{-y}\,\mathbf i-xe^{-y}\,\mathbf j


Setting the first components equal to one another, we can integrate both sides to find

\dfrac{\partial f}{\partial x}=e^{-y}\implies f(x,y)=xe^{-y}+g(y)

Differentiating both sides with respect to y gives

\dfrac{\partial f}{\partial y}=-xe^{-y}+\dfrac{\mathrm dg}{\mathrm dy}=-xe^{-y}
\implies\dfrac{\mathrm dg}{\mathrm dy}=0
\implies g(y)=C

so that

f(x,y)=xe^{-y}+C

By the fundamental theorem of calculus, we have that

\displaystyle\int_{\mathcal C}\mathbf F\cdot\mathrm d\mathbf r=\int_{\mathcal C}\nabla f\cdot\mathrm d\mathbf r=f(1,1)-f(0,0)=\frac1e
4 0
3 years ago
Find the average value of the function over the given interval. (Round your answer to three decimal places.) f(x) = −sin x, [0,
deff fn [24]

Answer with Step-by-step explanation:

We are given that

f(x)=-sin x

[0,\infty]]

Average value of the function is given gy

f_{avg}=\frac{1}{b-a}\int_{a}^{b}f(x)dx=\frac{1}{\pi-0}\int_{0}^{\pi}-sinx dx

f_{avg}=\frac{1}{\pi}[cosx]^{\pi}_{0}

Using the formula

\int sin xdx=-cos x

f_{avg}=\frac{1}{\pi}(cos\pi-cos0)

f_{avg}=\frac{1}{\pi}(-1-1)=-\frac{2}{\pi}

f(x)=f_{avg}

-sinx=-\frac{2}{\pi}

sinx=\frac{2}{\pi}

x=sin^{-1}(\frac{2}{\pi})=0.69radian

7 0
2 years ago
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