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2 years ago

HELP PLZ

Mathematics

1 answer:

postnew [5]2 years ago

4 0

Answer:

3/30 water

Step-by-step explanation:

3/5 water = 1 portion

x = 1/6 portion

x= (1/6 portion) (3/5 water) / 1 portion

x =3/30 water

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A ladder leaning against a building makes an angle of 78 degrees with the ground. The foot of the ladder is 5 feet from the buil

tatiyna

9514 1404 393

Answer:

24 feet

Step-by-step explanation:

The side adjacent to the angle is given, and the hypotenuse of the triangle is the unknown. The cosine relation applies:

Cos = Adjacent/Hypotenuse

hypotenuse = ladder length = (5 ft)/cos(78°) ≈ 24.0 ft

The ladder is about 24 feet long.

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3 years ago

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saveliy_v [14]

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2 years ago

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Juan is 3 years younger than half his aunts age. If Juan is 27 years old, how old is his aunt?

Ugo [173]

Juan’s aunt is 57 years old

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2 years ago

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Don’t understand this can someone help

pentagon [3]

1...
you need to find unknown measures in 1.ques. by using corresponding parts of similar triangle property..
THAT IS...
XY/PQ = YZ/QR =ZX/PR....
PUT VALUES IN THIS N SOLVE....

2....
use the property that ratio of corresponding sides of similar figures are equal....

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8 0

3 years ago

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P (2, 3) and Q (6, 10) are two points on the Cartesian plane.

lara31 [8.8K]

Step-by-step explanation:

Given:

$(x_1, \: y_1 ) =(2, \:3)\:\:\&\:\: (x_2, \: y_2) =(6, \:10)$

$l(PQ) = \sqrt{ {(x_1 - x_2)}^{2} + {(y_1 - y_2)}^{2}} \\ \\ = \sqrt{ {(2 - 6)}^{2} + {(3 - 10)}^{2}} \\ \\ = \sqrt{ {( - 4)}^{2} + {( - 7)}^{2}} \\ \\ = \sqrt{16 + 49} \\ \\ = \sqrt{65} \\ \\ \therefore \purple{ \boxed{ l(PQ) = 8.06 \: units}}\\\\$

Let S be the mid-point of PQ.

$\therefore S = \{\frac{x_1+x_2}{2}, \:\:\frac{y_1+y_2}{2}\} \\\\= \{\frac{2 +6}{2}, \:\:\frac{3+10}{2}\} \\\\= \{\frac{8}{2}, \:\:\frac{13}{2}\} \\\\\therefore S= \{4, \:\:6.5\} \\\\$

Equation of line PQ is given as:

$\frac{y-y_1}{y_1 - y_2}=\frac{x-x_1}{x_1 - x_2} \\\\\therefore \frac{y-3}{3 - 10}=\frac{x-2}{2 - 6} \\\\\therefore \frac{y-3}{-7}=\frac{x-2}{-4} \\\\\therefore \frac{y-3}{7}=\frac{x-2}{4} \\\\\therefore 4(y-3)=7(x-2)\\\\\therefore 4y-12=7x-14\\\\\therefore 7x-14 - 4y + 12=0\\\\\red{\boxed {\therefore 7x-4y - 2 =0}}$

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3 years ago

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