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velikii [3]
3 years ago
6

A baseball is struck by a batter at an angle such that it reaches its maximum height at the location of the pitcher – and just g

razes the top of the pitcher’s head (at an elevation of 1.50 m above the launch point of the baseball). The pitcher is a horizontal distance of 20.0 m from the point at which the ball was struck. What was the launch angle for the baseball?

Mathematics
1 answer:
Kobotan [32]3 years ago
3 0

Answer:

See it in the pic.

Step-by-step explanation:

See it in the pic.

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A dolphin is 41 feet underwater and ascends at a constant rate for 14 seconds until it reaches the surface.
Lana71 [14]

Answer:

It is not clear but I think it is

Step-by-step explanation:

20,-18

-45

5 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!WHAT IS THE ANSWER TO THIS QUESTION
Katarina [22]
I think C is the correct answer because the slope is not proportional however they are all around 2000. So multiply 2000 by 42 and you get 84,000. Which is about 81,000. 
4 0
3 years ago
0.6/10 as a fraction
mihalych1998 [28]

Answer:

I'm very confused because it seems you already have it in a fraction ut it'd be 6/10 I think and in percentage it would be 6%.

Step-by-step explanation:

Hope this was what you needed

8 0
3 years ago
How many groups of 20 can you make out of 100?
poizon [28]

5 it's super easy for me

8 0
3 years ago
The position function of a particle in rectilinear motion is given by s(t) = t3 – 12t2 + 45t + 4 for t ≥ 0 with t measured in se
Doss [256]

With position function

s(t)=t^3-12t^2+45t+4

the velocity of the particle is given by

\dfrac{\mathrm ds}{\mathrm dt}=3t^2-24t+45

The particle changes direction when its velocity changes sign. We have

\dfrac{\mathrm ds}{\mathrm dt}=0\implies t=3,t=5

so the particle's direction is reversed at two different times.

The acceleration is given by

\dfrac{\mathrm d}{\mathrm dt}\left[\dfrac{\mathrm ds}{\mathrm dt}\right]=\dfrac{\mathrm d^2s}{\mathrm dt^2}=6t-24

When t=3, the particle's position is s(3)=58 ft and its acceleration is s''(3)=-6 ft/s^2.

When t=5, the particle's position is s(5)=54 ft and its acceleration is s''(5)=6 ft/s^2.

3 0
3 years ago
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