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liubo4ka [24]
3 years ago
7

An unknown solution of triiodide registers an absorbance of 0.782 at 362 nm. A series of triiodide solutions of known concentrat

ion were analyzed at this wavelength and a standard curve was created. The equation of the best fit line from the standard curve was determined to be A = (3.2 x 10^-1 M^-1)c, where A= absorbance and c is the concentration of the solution. The constant value in this equation is the value of el. What is the concentration of the triiodide in the unknown solution?
Chemistry
1 answer:
kondaur [170]3 years ago
3 0
The standard curve was done at the wavelength of 362 nm for uniformity. We can use this function to determine the concentration at any absorbance value. At A = 0.782, c is,

<span>A = (3.2 x 10^-1 M^-1)c
0.782 = </span><span>(3.2 x 10^-1 M^-1)c
c = 2.44 M

The concentration of the triiodide solution  is 2.44 M.</span>
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A 0.5 mol sample of N2 is in a 6L container at 2 atm. what is the temperature of the gas in K
Andreas93 [3]

Answer:

300 K

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Diatomic Elements
  • Moles

<u>Gas Laws</u>

Ideal Gas Law: PV = nRT

  • <em>P</em> is pressure
  • <em>V</em> is volume
  • <em>n</em> is moles
  • <em>R</em> is gas constant
  • <em>T</em> is temperature

Explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] <em>n</em> = 0.5 mol N₂

[Given] <em>V</em> = 6 L

[Given] <em>P</em> = 2 atm

[Given] <em>R</em> = 0.0821 L · atm · mol⁻¹ · K⁻¹

[Solve] <em>T</em>

<em />

<u>Step 2: Solve for </u><em><u>T</u></em>

  1. Substitute in variables [Ideal Gas Law]:                                                          (2 atm)(6 L) = (0.5 mol)(0.0821 L · atm · mol⁻¹ · K⁻¹)T
  2. Multiply [Cancel out units]:                                                                               12 atm · L = (0.04105 L · atm · K⁻¹)T
  3. Isolate <em>T</em> [Cancel out units]:                                                                             292.326 K = T
  4. Rewrite:                                                                                                             T = 292.326 K

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig as our lowest.</em>

292.326 K ≈ 300 K

8 0
3 years ago
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The empirical formula is SCl_2.

The <em>empirical formula</em> (EF) is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the <em>molar ratio </em>of S to Cl.

Assume that you have 100 g of sample.

Then it contains 31.14 g S and 68.86 g Cl.

<em>Step</em> 1. Calculate the <em>moles of each element</em>

Moles of S = 31.14 g S × (1 mol S/(32.06 g S) = 0.971 30 mol S  

Moles of Cl = 68.86 g Cl × (1 mol Cl/35.45 g Cl) = 1.9425 mol Cl

<em>Step 2</em>. Calculate the <em>molar ratio</em> of each element

Divide each number by the smallest number of moles and round off to an integer

S:Cl = 0.971 30: 1.9425 = 1:1.9998 ≈ 1:2

<em>Step 3</em>: Write the <em>empirical formula</em>

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They are found the same way but use different symbols when found.

Explanation:

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