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3 years ago

A 0.5 mol sample of N2 is in a 6L container at 2 atm. what is the temperature of the gas in K

Chemistry

1 answer:

Andreas93 [3]3 years ago

8 0

Answer:

300 K

General Formulas and Concepts:

Atomic Structure

Diatomic Elements
Moles

Gas Laws

Ideal Gas Law: PV = nRT

P is pressure
V is volume
n is moles
R is gas constant
T is temperature

Explanation:

Step 1: Define

Identify variables

[Given] n = 0.5 mol N₂

[Given] V = 6 L

[Given] P = 2 atm

[Given] R = 0.0821 L · atm · mol⁻¹ · K⁻¹

[Solve] T

Step 2: Solve for T

Substitute in variables [Ideal Gas Law]: (2 atm)(6 L) = (0.5 mol)(0.0821 L · atm · mol⁻¹ · K⁻¹)T
Multiply [Cancel out units]: 12 atm · L = (0.04105 L · atm · K⁻¹)T
Isolate T [Cancel out units]: 292.326 K = T
Rewrite: T = 292.326 K

Step 3: Check

Follow sig fig rules and round. We are given 1 sig fig as our lowest.

292.326 K ≈ 300 K

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Answer:

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So correct order for slowest rate of diffusion (highest molar mass) to fastest rate of diffusion (lowest molar mass) is :

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