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Pie
3 years ago
8

PLEASE HELP, I NEED TO GET THIS DONE TODAY

Chemistry
1 answer:
luda_lava [24]3 years ago
4 0

The balanced reaction is

3Na3PO4  +  2CuSO4  ------>  3Na2SO4  + Cu3(PO4)2

To balance this reaction of double displacement, we see first that this reaction maintain the valence numbers of every atom.

Then, to have the same value of Na in the two sides of the reaction we multiply for the number of the other side. So,

(Na3PO4)x 2

(Na2SO4)x3

As we can see either, we need to balance PO4 cause there are two molecules of this in the reactant side, so we have two molecules of PO4 in the product either.

Then we get

3Na3PO4  +  2CuSO4  ------>  3Na2SO4  + Cu3(PO4)2

To probe that balance was correct, you can verify that the charges are exactly the opposite.

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Ca (ClO) 2<br> Spell out the full name of the compound.
antoniya [11.8K]
Calcium hypochlorite
5 0
4 years ago
using the Bohr model for hydrogen: energy = hc/wavelength = 2.18 x 10^-18 Joules (1/nf2 - 1/ni2) N=15 to n=5
soldier1979 [14.2K]

Answer:

Energy lost is 7.63×10⁻²⁰J

Explanation:

Hello,

I think what the question is requesting is to calculate the energy difference when an excited electron drops from N = 15 to N = 5

E = hc/λ(1/n₂² - 1/n₁²)

n₁ = 15

n₂ = 5

hc/λ = 2.18×10⁻¹⁸J (according to the data)

E = 2.18×10⁻¹⁸ (1/n₂² - 1/n₁²)

E = 2.18×10⁻¹⁸ (1/15² - 1/5²)

E = 2.18×10⁻¹⁸ ×(-0.035)

E = -7.63×10⁻²⁰J

The energy lost is 7.63×10⁻²⁰J

Note : energy is lost / given off when the excited electron jumps from a higher energy level to a lower energy level

5 0
3 years ago
Sulfuric acid (H2SO4) has a molar mass of 98.1 g/mol. How many oxygen atoms are found in 75.0 g of H2SO4? A. 1.15 × 10^23 B. 1.8
Margarita [4]

Answer:

B

Explanation:

first find the no. Of moles of H2SO4

=  75/98.1

= 0.7645

Next step

In on mole of H2SO4 the no.of oxygen atom is 4.

1 H2SO4 : 4 O

0.7645  : x                     x= 0.7645x4= 3.0581

next multiply avogadros constant

3.0581 x 6.022× 10^23 =1.84x10^24

3 0
4 years ago
Consider the following first order decomposition reaction with a half-life of 65 seconds at a given temperature:
katrin [286]

Answer:

130

Explanation:

This is because that 3atm of N2O4 is used up for the 6atm of NO2, so 1 atm N2O4 is left. Resulting in In(1/4).

6 0
3 years ago
A. What mass (in g) of KIO3 is needed to prepare 50.0 mL of 0.20 M KIO3?
rewona [7]

Answer:

A. 2.139g of KIO3

B. 26.67mL

Explanation:Please see attachment for explanation

3 0
3 years ago
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