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Anastasy [175]
3 years ago
11

How can some of the difficulties caused by the Down Syndrome be over come?

Chemistry
1 answer:
Salsk061 [2.6K]3 years ago
4 0
There is no single, standard treatment for down syndrome.
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Percentage of isotopes in 35/17 Cl and 37/17 Cl with the molar mass of chlorine as 35.5g and the mass of each nucleon to be 1.00
AlekseyPX

Answer:

The abundance of 35/17 Cl is 75% and 25% of 37/17Cl

Explanation:

The molar mass of an atom is defined as the sum of the masses of each isotope times its abundance, that is:

35.5amu = 35amu*X + 37amu*Y <em>(1)</em>

<em>Where X is the abundance of the 35/17Cl and Y the abundance of 37/17 Cl</em>

<em />

As there are just these 2 isotopes and the abundances of both isotopes = 1:

X + Y = 1 <em>(2)</em>

<em></em>

Replacing (2) in (1):

35.5 = 35X + 37(1-X)

35.5 = 35X + 37 - 37X

-1.5 = -2X

X = 0.75 = 75%

And Y = 100-75% = 25%

<h3>The abundance of 35/17 Cl is 75% and 25% of 37/17Cl</h3>
4 0
3 years ago
Given that:2NO (g)→N2 (g)+O2 (g)N2 (g)+O2 (g)+Cl2 (g)→2NOCl (g) has an enthalpy change of −180.6 kJ has an enthalpy change of 10
likoan [24]

Answer:

Explanation:

It is possible to answer this question knowing Hess's law that says you can sum half-reactions enthalpy cahnge to obtain enthalpy change of the total reaction. Using the reactions:

<em>(1) </em>2NO(g) → N₂(g)+O₂(g) ΔH = -180,6 kJ

<em>(2) </em>N₂(g) + O₂(g) + Cl₂(g) → 2NOCl(g) ΔH = +103,4 kJ

The reverse reactions of (1) and (2) are:

<u>N₂(g)+O₂(g)</u> → 2NO(g) ΔH = +180,6 kJ

2NOCl(g) → <u>N₂(g) + O₂(g)</u> + Cl₂(g) ΔH = -103,4 kJ

The sum of these reactions is:

2NOCl(g) → 2NO(g) + Cl₂(g) ΔH = +180,6 kJ -103,4 kJ = <em>77,2 kJ</em>

<em />

I hope it helps!

6 0
2 years ago
When 2.00 g of methane are burned in a bomb calorimeter, the change in temperature is 3.08°C. The heat capacity of the calorimet
melisa1 [442]

Answer:

The approximate molar enthalpy of combustion of this substance is -66 kJ/mole.

Explanation:

First we have to calculate the heat gained by the calorimeter.

q=c\times \Delta T

where,

q = Heat gained = ?

c = Specific heat = 2.68 kJ/^oC

ΔT =  The change in temperature = 3.08°C

Now put all the given values in the above formula, we get:

q=2.68 kJ/^oC\times 3.08^oC

q=8.2544 kJ

Now we have to calculate molar enthalpy of combustion of this substance :

\Delta H_{comb}=-\frac{q}{n}

where,

\Delta H_{comb} = enthalpy change = ?

q = heat gained = 8.2544kJ

n = number of moles methane = \frac{\text{Mass of methane}}{\text{Molar mass of methane }}=\frac{2.00 g}{16.042 g/mol}=0.1247 mole

\Delta H_{comb}=-\frac{8.2544 kJ}{0.1247 mole}=-66.21 kJ/mole\approx -66 kJ/mole

Therefore,  the approximate molar enthalpy of combustion of this substance is -66 kJ/mole.

6 0
3 years ago
_______ is the process in which light energy is transformed into food energy. A.life B.photosynthesis C.abiotic D.biotic
kolezko [41]

Answer:

B) Photosynthesis is the process in which light energy is transformed into food energy.

4 0
2 years ago
Read 2 more answers
Is the narrator male or female in the story leaving?​
AlladinOne [14]
The narrator is a female

Hope this helps
8 0
3 years ago
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