How can some of the difficulties caused by the Down Syndrome be over come?

Chemistry

1 answer:

Salsk061 [2.6K]3 years ago

4 0

There is no single, standard treatment for down syndrome.

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The first stage of a(n) _____________________ is when clouds form; this is the cumulus stage.

alekssr [168]

Answer:

I think it might towering cumulonimbus or cumulonimbus

5 0

4 years ago

Consider the combustion of octane (C8H18)

Masja [62]

First, you have to find now many moles of octane are present in 191.6g of octane. To do this you need to do this you need to divide 191.6g by its molar mass (which is 114g/mol). This will give you 1.681 moles of octane. Then you need to use the fact that 2 moles of octane are us ed to make 16 moles of carbon dioxide to find how many moles of carbon dioxide 1.681mole of octane produces. To do this you need to multiply 1.681mole by 16/2 to get 13.45mol carbon dioxide. The final step is to find the number of grams presswnt in 13.446 moles of carbon dioxide. To do this you need to multiply 13.446 mole by carbon dioxides molar mass (which is 44g/mol) to get 591.6 g of carbon dioxide.
Therefore, 591.6g of carbon dioxide is produced when 191.6 grams of octane is burned.

I hope this helps. Let me know in the comments if anything is unclear.

8 0

3 years ago

A sample of helium gas occupies 355ml at 23°c. if the container the he is in is expanded to 1.50 l at constant pressure, what is

ss7ja [257]

Answer: The final temperature would be 1250.7 K.

Explanation: We are given a sample of helium gas, the initial conditions are:

$V_{initial}=355mL=0.355L$ (Conversion factor: 1L = 1000 mL)

$T_{initial}=23\°C=296K$ (Conversion Factor: 1° C = 273 K)

The same gas is expanded at constant pressure, so the final conditions are:

$V_{initial}=1.50L$

$T_{initial}=?K$

To calculate the final temperature, we use Charles law, which states that the volume of the gas is directly proportional to the temperature at constant pressure.

$V\propto T$