Answer:
vertex at (1, -3)
Step-by-step explanation:
When x = 0
y² + 6y + 1 = 0
y² + 6y + = -1
y² + 6y + 9 = -1 + 9
(y + 3)² = 8 or (-y - 3)² = 8
y + 3 = √8 or -y - 3 = √8
y = - 3 +√8 or y = -3 - √8
(0, - 3 +√8) and (0, -3 - √8)
The mid point between these two is the average
y = ( - 3 + √8 + -3 - √8) / 2 = - 3
y² + 6y + 8x + 1 = 0
(-3)² + 6(-3) + 8x + 1 = 0
9 - 18 + 1 = -8x
- 8 = -8x
x = 1
Answer:
yes
Step-by-step explanation:
2 plus 2 is 4
F(y) = y + y^2 - 3
f(-2) = -2 + (-2^2) - 3
f(-2) = -2 + 4 - 3
f(-2) = -1
f(-4) = -4 + (-4^2) - 3
f(-4) = -4 + 16 - 3
f(-4) = 9
f(0) = 0 + 0^2 - 3
f(0) = -3
f(2) = 2 + 2^2 - 3
f(2) = 2 + 4 - 3
f(2) = 3
f(4) = 4 + 4^2 - 3
f(4) = 4 + 16 - 3
f(4) = 17
2m-6=48
+6 +6
__________
2m= 42
÷2 ÷2
_________
m=21
m=21 is the answer
Answer:
144
Step-by-step explanation:
First: 6x
Second: 6x+6
Third: 6x+12
Fourth: 6x+18
- Since they're multiples of 6
Subract 36 from each side give us...
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