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dimaraw [331]
3 years ago
10

The coordinates of point T are (0, 3). The midpoint of ST is (4, -4). Find the coordinates of point S​

Mathematics
1 answer:
borishaifa [10]3 years ago
4 0
How am i supposed to answer
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The sequence below shows the total number of days Francisco had used his
drek231 [11]
1 week because ye. 47
3 0
3 years ago
2x5x1742x2133+12/4= PlS hellllp
Fynjy0 [20]

Answer:

37,156,863

Step-by-step explanation:

2 x 5 x 1742 x 2133 + 12/4 =

10 x 1742 x 2133 +12/4 =

17420 x 2133 + 3=

37,156,860 + 3 =

37,156,863

8 0
3 years ago
Claudia says that she used the GCF to factor the expression 20x + 100xy as 20(x + 5xy). Is she correct? Explain.
Keith_Richards [23]

No, She is not correct.

Step-by-step explanation:

To find the greatest common factor of the expression 20x + 100xy.

Given expression 20x + 100xy.

Let us factor the expression 20x + 100xy.

Now take the common factor in the expression 20x + 100xy.

The common factor is 20x.

So, 20x + 100xy = 20x( 1+ 5y)

But Claudia says that the greatest common factor is 20(x+5xy).

The GCF is wrong.

So, she is not correct.

8 0
3 years ago
Find an equation for the line that passes through the given point and satisfies the given conditions. 11) 11) p = ( 9 , 2 ); per
geniusboy [140]

You can use the direction vector as the coefficients of x and y for a line through (0, 0) perpendicular to that direction: x + y = 0. (A common factor of 4 can be removed from the coefficients.)

Translating the line up 2 and right 9, so it goes through the given point, we get ...

... (x -9) +(y -2) = 0

or

... x + y = 11

5 0
3 years ago
A fluid moves through a tube of length 1 meter and radius r=0.006±0.00025 meters under a pressure p=4⋅105±2000 pascals, at a rat
iris [78.8K]

Answer:

Maximum error for viscosity is 17.14%

Step-by-step explanation:

We know that everything is changing with respect to the time, "r" is changing with respect to the time, and also "p" just "v" will not change with the time according to the information given, so we can find the implicit derivative with respect to the time, and since

n = (\frac{\pi}{8}) (\frac{pr^4}{v})\\

The implicit derivative with respect to the time would be

\frac{dn}{dt}  = \frac{\pi}{8} ( \frac{r^4}{v} \frac{dp}{dt}  + \frac{4pr^3}{v}\frac{dr}{dt} )

If we multiply everything by    dt   we get  

dn  = \frac{\pi}{8} ( \frac{r^4}{v} dp  + \frac{4pr^3}{v}  dr})

Remember that  the error is given by   \frac{dn}{n}   therefore doing some algebra we get that

\frac{dn}{n}  =    4 \frac{dr}{r}  +  \frac{dp}{p}

Since,    r = 0.006   ,   dr = 0.00025 ,  p = 4*105   ,   dp = 2000  we get that

\frac{dn}{n} = 0.1714

Which means that  the maximum error for viscosity is 17.14%.  

5 0
3 years ago
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