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OLEGan [10]
4 years ago
12

If 3 dogs eat 4 pounds of dog food a day how many dogs eat 15 pounds of food a day

Mathematics
1 answer:
pogonyaev4 years ago
7 0

Answer: 11dogs

Step-by-step explanation: 3 dogs eat 4 pounds of food a day. Therefore,

One dog eats, 4/3 pounds of food

For 15 pounds of food, since one dog eats 4/3 pounds of food

=15/(4/3)

=11.25

Therefore 11 dogs eat 15 pounds of food

You might be interested in
Determine the five-number summary for this data set, taking into account any outliers. 10 13 15 12 12 4 12 17 12 13 15 18 10 11
TiliK225 [7]

The value of the median, lower and upper quartile

  • Median = 21.5
  • lower quartile = 12
  • upper quartile = 29

<h3>What is the five-number summary for this data set?</h3>

The minimum value = 10

The maximum value = 38

The median is the value that is found in the center of the data when it is ordered from lowest to highest. In the event that there is no value that precisely corresponds to the center, the value will be determined by taking the average of the values that are located on each side of the middle.

10  11  12  15  19  24  27  29  33  38

Median = 21.5

The intermediate value of the data that is located to the left of the median is known as the lower quartile.

10  11  12  15  19

lower quartile = 12

The intermediate value of the data that is located to the right of the median is known as the upper quartile.

24  27  29  33  38

upper quartile = 29

In conclusion, the 5 number summary is 10, 12, 21.5, 29, 38 → A

Read more about median

brainly.com/question/28060453

#SPJ1

3 0
2 years ago
Due to a packaging error, 4 cans labeled diet soda were accidentally filled with regular soda and placed in a 12 pack carton of
Sophie [7]

Answer:

Probability that both cans were regular soda =  \frac{1}{11}

Step-by-step explanation:

Probability = \frac{Desired outcome}{Total possible outcomes}

We are given 12 total number of cans; 4 cans have been accidentally filled with diet soda.

Probability that first can is a regular soda:

Outcome that first can is a regular soda will give us the number of regular soda available which are 4

Using formula of probability

Total possible outcomes are, n(total) = 12

Desired outcome: 4 (cans of regular soda)

P(1st can) =  \frac{4}{12} = \frac{1}{3}

Probability that 2nd can is a regular soda:

<em>As we have already taken a can of regular soda from the pack, the total soda in the pack now 11 and the regular soda left are 3.</em>

Total possible outcomes are, n(total) = 11

Desired outcome: 3 (cans of regular soda as one has already been taken)

P(2nd can) =  \frac{3}{11}


Probability that both cans are regular soda:

P(both) = P(1st can) × P(2nd can)

             = \frac{1}{3} * \frac{3}{11}

             = \frac{1}{11}

3 0
3 years ago
Read 2 more answers
Plsss help meee 45 points plus brainliest
romanna [79]

<em>Hello There!!</em>

Let us call X the equal distances GH = HI = IJ

GH = X

HI = X

IJ = X

Note that HJ = HI + IJ, so

HJ = X + X

10 = 2X

X = 5

Well, We're looking at figure we can conclude that:

GJ + JK = GK

GJ = GH + HI + IJ

GJ = 15

GJ + JK = GK

15 + JK = 24

JK = 9

GH = X = 5

HI = X = 5

IJ = X = 5

JK = 9

HopeThisHelpsYou!

_{Losersbrazts}

5 0
3 years ago
The answer to the problem​
Kipish [7]

Answer:

Step-by-step explanation:

the problem is, there is no problem ;)

4 0
3 years ago
Question 17 please help
kramer
\sqrt{9x^2} / \sqrt{18y^2}
after taking sqrt both side

3x/\sqrt{9*2y^2}

3x/3y√2
x/√2y
multiply both denomenator and numerator by√2
√2x/2y

Answer is A

8 0
3 years ago
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