If 3 dogs eat 4 pounds of dog food a day how many dogs eat 15 pounds of food a day

Mathematics

1 answer:

pogonyaev3 years ago

7 0

Answer: 11dogs

Step-by-step explanation: 3 dogs eat 4 pounds of food a day. Therefore,

One dog eats, 4/3 pounds of food

For 15 pounds of food, since one dog eats 4/3 pounds of food

=15/(4/3)

=11.25

Therefore 11 dogs eat 15 pounds of food

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BRAINLIEST IF CORRECT PLEASE DONT ANSWER IF YOU DONT KNOW OR REPORTED 50 POINTS I NEED MY GRADES TO BE BETTER

weqwewe [10]

Answer:

B.166 11/12

Step-by-step explanation:

To handle this problem better, we can separate the fraction and integer portions to look at the whole situation better.

First, let's only look at the integers. Anthony flew up his drone 125 feet (translating to +125), allowed it to drop 14 feet (translating to -14), and then flew it up for 55 feet (translating to +55). Hence, only considering the integers, the total change in the drone's position would be (125 - 14 + 55) feet, which equates to 166 feet.

You'd probably have already noticed this answer is quite close to B. 166 11/12 feet, but let's keep on going for now.

On the fraction part, he flew his drone up 1/2 feet, allowed it to drop 1/3 feet, and then flew it up for 3/4 feet, translating to (1/2 - 1/3 + 3/4) feet.

Hence, after making all fractions share the same denominator, that same equation would change to (6/12 - 4/12 + 9/12) feet, which equals to 11/12 feet.

Finally, the total magnitude of the drone's position would be (166 + 11/12) feet, which is equal to B.166 11/12 feet.

Hope this helped!

6 0

2 years ago

Read 2 more answers

Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays

katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

Answer: The half life of the sample of phosphorus-32 is $14.28days^{-1}$